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Ch. 5 - Systems of Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 6, Problema 59

Exercises 57–59 will help you prepare for the material covered in the next section. Solve: {A+B=32A−2B+C=174A−2C=14\(\begin{cases}\) A + B = 3 \\ 2A - 2B + C = 17 \\ 4A - 2C = 14 \(\end{cases}\)

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1
Identify the system of equations given: \(A + B = 3\), \(2A - 2B + C = 17\), \(4A - 2C = 14\).
From the first equation, express one variable in terms of the other. For example, solve for \(B\): \(B = 3 - A\).
Substitute the expression for \(B\) into the second equation to eliminate \(B\): \(2A - 2(3 - A) + C = 17\).
Simplify the second equation after substitution to get an equation in terms of \(A\) and \(C\) only.
Use the third equation \(4A - 2C = 14\) along with the simplified second equation to solve the system of two equations with two variables (\(A\) and \(C\)). Then back-substitute to find \(B\).

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