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Ch. 5 - Systems of Equations and Inequalities
Blitzer - College Algebra 8th Edition
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Tutti i libri di testoBlitzer 8th EditionCh. 5 - Systems of Equations and InequalitiesProblema 37
Capitolo 6, Problema 37

In Exercises 29–42, solve each system by the method of your choice. {x2+(y−2)2=4x2−2y=0\(\begin{cases}\) x^2 + (y - 2)^2 = 4 \\ x^2 - 2y = 0 \(\end{cases}\)

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1
Identify the system of equations to solve: \(x^2 + (y - 2)^2 = 4\) and \(x^2 - 2y = 0\).
From the second equation, isolate \(y\) in terms of \(x\): \(x^2 - 2y = 0 \implies 2y = x^2 \implies y = \frac{x^2}{2}\).
Substitute the expression for \(y\) from step 2 into the first equation: \(x^2 + \left( \frac{x^2}{2} - 2 \right)^2 = 4\).
Expand and simplify the equation from step 3 to form a polynomial equation in terms of \(x\) only. This will involve squaring the binomial and combining like terms.
Solve the resulting polynomial equation for \(x\). Then, substitute each \(x\) value back into \(y = \frac{x^2}{2}\) to find the corresponding \(y\) values, giving the solution points \((x, y)\) for the system.

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Solving Systems of Equations

A system of equations consists of two or more equations with the same variables. Solving the system means finding all variable values that satisfy all equations simultaneously. Methods include substitution, elimination, and graphing, chosen based on equation types and complexity.
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Solving Systems of Equations - Substitution

Equations of Circles

The equation x² + (y - k)² = r² represents a circle with center at (0, k) and radius r. Understanding this form helps identify geometric constraints and possible solution points when combined with other equations in a system.
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Circles in Standard Form

Substitution Method

The substitution method involves solving one equation for one variable and substituting that expression into the other equation. This reduces the system to a single equation with one variable, simplifying the process of finding solutions.
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Choosing a Method to Solve Quadratics
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