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Ch. 5 - Systems of Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 6, Problema 39

In Exercises 31–42, solve by the method of your choice. Identify systems with no solution and systems with infinitely many solutions, using set notation to express their solution sets. x/4 - y/4 = −1 x + 4y = -9

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Start by writing the system of equations clearly: x4 - y4 = -1 and x + 4y = -9.
Multiply the first equation by 4 to eliminate the denominators: 4 \(\times\) \(\left\)( \(\frac{x}{4}\) - \(\frac{y}{4}\) \(\right\)) = 4 \(\times\) (-1), which simplifies to x - y = -4.
Now you have the system: x - y = -4 and x + 4y = -9. Use either substitution or elimination to solve this system. For elimination, subtract the first equation from the second to eliminate x: (x + 4y) - (x - y) = -9 - (-4).
Simplify the subtraction: x + 4y - x + y = -9 + 4, which reduces to 5y = -5. Solve for y by dividing both sides by 5.
Substitute the value of y back into one of the original equations (for example, x - y = -4) to solve for x. After finding both x and y, express the solution as an ordered pair (x, y). If you find contradictory statements or infinite solutions during the process, identify and express those accordingly using set notation.

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