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Ch. 5 - Systems of Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 6, Problema 13

In Exercises 5–18, solve each system by the substitution method. 2x + 5y = - 4 3x - y = 11
Two linear equations for solving a system by substitution method in college algebra.

Guida verificata passo dopo passo
1
Start with the given system of equations: 2x+5y=-43x-y=11.
Solve one of the equations for one variable in terms of the other. For example, solve the second equation for y: 3x - y = 11 becomes y = 3x - 11.
Substitute the expression for y from step 2 into the first equation: replace y in 2x + 5y = -4 with 3x - 11 to get 2x + 5(3x - 11) = -4.
Simplify and solve the resulting equation for x. This will give you the value of x in terms of numbers.
Substitute the value of x back into the expression for y found in step 2 to find the corresponding value of y. This completes the solution to the system.

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