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Ch. 5 - Systems of Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 6, Problema 11

Solve each system in Exercises 5–18. {2x−4y+3z=17x+2y−z=04x−y−z=6\(\begin{cases}\) 2x - 4y + 3z = 17 \\ x + 2y - z = 0 \\ 4x - y - z = 6 \(\end{cases}\)

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1
Write down the system of equations clearly: \[2x - 4y + 3z = 17\] \[x + 2y - z = 0\] \[4x - y - z = 6\]
Choose one equation to express one variable in terms of the others. For example, from the second equation, solve for \[x\]: \[x = -2y + z\]
Substitute the expression for \[x\] into the first and third equations to eliminate \[x\], resulting in two equations with only \[y\] and \[z\].
Simplify these two new equations and solve the resulting system of two equations with two variables (\[y\] and \[z\]) using either substitution or elimination.
Once you find \[y\] and \[z\], substitute these values back into the expression for \[x\] to find the value of \[x\].

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