Skip to main content
Ch. P - Fundamental Concepts of Algebra
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 1, Problema 58

Factor using the formula for the sum or difference of two cubes. x3+64x^3+64

Guida verificata passo dopo passo
1
Recognize that the expression \(x^3 + 64\) is a sum of two cubes because \(64\) can be written as \$4^3$.
Recall the formula for the sum of two cubes: $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$.
Identify \(a = x\) and \(b = 4\) in the expression \(x^3 + 4^3\).
Apply the sum of cubes formula: \((x + 4)(x^2 - 4x + 16)\).
Write the fully factored form as \((x + 4)(x^2 - 4x + 16)\).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
3m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Sum of Cubes Formula

The sum of cubes formula is used to factor expressions of the form a^3 + b^3. It states that a^3 + b^3 = (a + b)(a^2 - ab + b^2). This formula helps break down cubic expressions into simpler polynomial factors.
Video consigliato:
03:41
Special Products - Cube Formulas

Identifying Perfect Cubes

To apply the sum or difference of cubes formula, recognize each term as a perfect cube. For example, x^3 is the cube of x, and 64 is the cube of 4 since 4^3 = 64. Correct identification is essential for accurate factoring.
Video consigliato:
03:41
Special Products - Cube Formulas

Factoring Polynomials

Factoring polynomials involves rewriting them as products of simpler polynomials. Using special formulas like the sum or difference of cubes simplifies complex expressions, making it easier to solve equations or analyze functions.
Video consigliato:
07:30
Introduction to Factoring Polynomials