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Ch. 13 - Alcohols, Ethers and Related Compounds: Substitution and Elimination
Mullins - Organic Chemistry: A Learner Centered Approach 1st Edition
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471Non è quello che usi tu?Cambia libro di testo
Capitolo 12, Problema 28b

Predict the product of the following reactions.
(b)

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Step 1: Analyze the reactant structure. The molecule contains a secondary alcohol group (-OH) attached to a chiral carbon. The reaction involves HCl, which suggests an acid-catalyzed substitution reaction.
Step 2: Understand the mechanism. In the presence of HCl, the hydroxyl group (-OH) will be protonated to form water (H2O), a good leaving group. This step facilitates the formation of a carbocation intermediate.
Step 3: Consider carbocation stability. The secondary carbocation formed after the departure of water is relatively stable. No rearrangement is expected since the secondary carbocation is not adjacent to a more stable tertiary position.
Step 4: Nucleophilic attack. The chloride ion (Cl⁻) from HCl will act as a nucleophile and attack the carbocation, leading to the formation of a new C-Cl bond.
Step 5: Predict stereochemistry. Since the reaction proceeds via a carbocation intermediate, the product will likely be a racemic mixture due to the planar nature of the carbocation, allowing attack from either side.

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