Skip to main content
Ch.1 - Structure and Bonding
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728Non è quello che usi tu?Cambia libro di testo
Capitolo 1, Problema 55e

Draw orbital pictures of the pi bonding in the following compounds:
e. CH3CH=C=CHCH3

Guida verificata passo dopo passo
1
Identify the structure of the compound CH3CH=C=CHCH3. This compound is known as 2,3-pentadiene, which contains two double bonds between carbon atoms.
Recognize that each double bond consists of one sigma (σ) bond and one pi (π) bond. The pi bond is formed by the sideways overlap of p orbitals.
For the first double bond (CH3CH=C), identify the carbon atoms involved in the pi bond. These are the second and third carbon atoms in the chain.
Draw the p orbitals on the second and third carbon atoms. These p orbitals will overlap sideways to form the first pi bond.
Repeat the process for the second double bond (C=CHCH3), involving the third and fourth carbon atoms. Draw the p orbitals on these carbon atoms and show their sideways overlap to form the second pi bond.

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
3m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Pi Bonding

Pi bonds are formed by the sideways overlap of p orbitals, which are not involved in sigma bonding. In a molecule, pi bonds provide additional bonding strength and are typically found in double and triple bonds. Understanding pi bonding is crucial for visualizing the electron cloud distribution in unsaturated hydrocarbons like alkenes and alkynes.
Video consigliato:
01:05
Sigma bonds and pi bonds

Orbital Hybridization

Orbital hybridization involves the mixing of atomic orbitals to form new hybrid orbitals, which can form sigma and pi bonds. In the compound CH3CH=C=CHCH3, the central carbon atoms are sp2 and sp hybridized, allowing for the formation of both sigma and pi bonds. Recognizing the hybridization state helps in predicting the geometry and bonding of the molecule.
Video consigliato:
04:58
Bond sites, hybridization, and intermediate orbitals

Molecular Geometry

Molecular geometry refers to the three-dimensional arrangement of atoms in a molecule. It is determined by the hybridization of the central atoms and the presence of pi bonds. For CH3CH=C=CHCH3, understanding the linear and trigonal planar geometries around the sp and sp2 hybridized carbons is essential for accurately drawing the orbital pictures of pi bonding.
Video consigliato:
07:44
Molecular Geometry Explained.