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Ch 09: Work and Kinetic Energy
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Non è quello che usi tu?Cambia libro di testo
Capitolo 9, Problema 69c

Finish the solution of the problem.
T−(1500kg)(9.8m/s2)=(1500kg)(1.0m/s2)T-(1500\,\(\text{kg}\))(9.8\,\(\text{m/s}\)^2)=(1500\,\(\text{kg}\))\(\left\)(1.0\,\(\text{m/s}\)^2\(\right\))
P=T(2.0m/s)P=T(2.0\,\(\text{m/s}\))

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Identify the forces acting on the object. The equation T - (1500 \; \(\text{kg}\))(9.8 \; \(\text{m/s}\)^2) = (1500 \; \(\text{kg}\))(1.0 \; \(\text{m/s}\)^2) represents the net force acting on the object, where T is the tension in the rope, (1500 \; \(\text{kg}\))(9.8 \; \(\text{m/s}\)^2) is the gravitational force, and (1500 \; \(\text{kg}\))(1.0 \; \(\text{m/s}\)^2) is the net force due to acceleration.
Rearrange the equation to solve for the tension T. Add the gravitational force term to both sides: \( T = (1500 \; \text{kg})(9.8 \; \text{m/s}^2) + (1500 \; \text{kg})(1.0 \; \text{m/s}^2) \).
Substitute the values into the equation to calculate T. This will give you the total tension in the rope.
Next, use the equation for power: \( P = T \cdot v \), where \( v = 2.0 \; \text{m/s} \) is the velocity. Substitute the value of T from the previous step into this equation.
Simplify the expression for power \( P \) by multiplying the tension \( T \) with the velocity \( v \). This will give you the power output in watts.

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Tension in a Rope

Tension is the force transmitted through a rope, string, or cable when it is pulled tight by forces acting from opposite ends. In this context, the tension (T) is calculated based on the weight of the object (1500 kg) and the acceleration due to gravity (9.8 m/s²), which helps determine the net force acting on the system.
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Calculating Tension in a Pendulum with Energy Conservation

Newton's Second Law of Motion

Newton's Second Law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This principle is crucial for solving the problem, as it allows us to relate the forces acting on the 1500 kg mass to its acceleration (1.0 m/s²) and calculate the resulting tension in the rope.
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Intro to Forces & Newton's Second Law

Power Calculation

Power is defined as the rate at which work is done or energy is transferred over time. In this problem, power (P) can be calculated using the formula P = T * v, where T is the tension and v is the velocity (2.0 m/s). Understanding how to compute power is essential for finishing the solution and interpreting the physical significance of the forces involved.
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Write a realistic problem for which this is the correct equation(s).

T−(1500kg)(9.8m/s2)=(1500kg)(1.0m/s2)T-(1500\,\(\text{kg}\))(9.8\,\(\text{m/s}\)^2)=(1500\,\(\text{kg}\))\(\left\)(1.0\,\(\text{m/s}\)^2\(\right\))

P=T(2.0m/s)P=T(2.0\,\(\text{m/s}\))

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Draw a pictorial representation.

T−(1500kg)(9.8m/s2)=(1500kg)(1.0m/s2)T-(1500\,\(\text{kg}\))(9.8\,\(\text{m/s}\)^2)=(1500\,\(\text{kg}\))\(\left\)(1.0\,\(\text{m/s}\)^2\(\right\))

P=T(2.0m/s)P=T(2.0\,\(\text{m/s}\))

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