The motor of an electric drill draws a 3.5 A rms current at the power-line voltage of 120 V rms. What is the motor's power if the current lags the voltage by 20°?

Guida verificata passo dopo passo

Step 1: Recall the formula for calculating the real power (P) in an AC circuit: \( P = V_{\text{rms}} \cdot I_{\text{rms}} \cdot \cos(\phi) \), where \( V_{\text{rms}} \) is the root mean square voltage, \( I_{\text{rms}} \) is the root mean square current, and \( \phi \) is the phase angle between the current and voltage.

Step 2: Identify the given values from the problem: \( V_{\text{rms}} = 120 \; \text{V} \), \( I_{\text{rms}} = 3.5 \; \text{A} \), and \( \phi = 20^\circ \).

Step 3: Convert the phase angle \( \phi \) from degrees to radians if necessary, as some calculations may require it. Use the conversion formula \( \phi_{\text{radians}} = \phi_{\text{degrees}} \cdot \frac{\pi}{180} \).

Step 4: Substitute the given values into the power formula: \( P = 120 \cdot 3.5 \cdot \cos(20^\circ) \).

Step 5: Use a calculator or trigonometric table to find \( \cos(20^\circ) \), then multiply the values to compute the motor's real power. Ensure the units of the final result are in watts (W).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

RMS Current and Voltage

RMS (Root Mean Square) values represent the effective values of alternating current (AC) and voltage. For AC circuits, RMS values allow for the calculation of power as they provide a measure equivalent to a DC value that would deliver the same power. In this case, the drill operates at 3.5 A rms and 120 V rms, which are essential for determining the power consumed.

Video consigliato:

Percorso guidato

07:14

RMS Current and Voltage

Power Factor

The power factor is a measure of how effectively electrical power is being converted into useful work output. It is defined as the cosine of the phase angle (φ) between the current and voltage waveforms. In this scenario, with a phase lag of 20°, the power factor can be calculated as cos(20°), which is crucial for determining the real power consumed by the motor.

Video consigliato:

Percorso guidato

06:00

Power

Real Power Calculation

Real power, measured in watts (W), is the actual power consumed by an electrical device to perform work. It can be calculated using the formula P = V_rms * I_rms * power factor. For the electric drill, substituting the given values of voltage, current, and the calculated power factor will yield the motor's real power output.

Video consigliato:

Percorso guidato

06:00

Power

Pratica correlata

Domanda del libro di testo

The heating element of a toaster dissipates 1500 W when connected to a 120 V/60 Hz power line. What is its resistance?

149

views

Domanda del libro di testo

A resistor dissipates 2.0 W when the rms voltage of the emf is 10.0 V. At what rms voltage will the resistor dissipate 10.0 W?

146