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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
3장, 문제 3.9.13

Find d/dx (In(xe^x)) without using the Chain Rule and the Product Rule.

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Step 1: Begin by recognizing that the expression inside the logarithm is a product: \(xe^x\). We can use the property of logarithms that \(\ln(a \cdot b) = \ln(a) + \ln(b)\). Apply this property to rewrite the expression as \(\ln(x) + \ln(e^x)\).
Step 2: Simplify \(\ln(e^x)\). Recall that \(\ln(e^x) = x \cdot \ln(e)\), and since \(\ln(e) = 1\), this simplifies to \(x\). Therefore, the expression becomes \(\ln(x) + x\).
Step 3: Differentiate \(\ln(x)\) with respect to \(x\). The derivative of \(\ln(x)\) is \(\frac{1}{x}\).
Step 4: Differentiate \(x\) with respect to \(x\). The derivative of \(x\) is simply \(1\).
Step 5: Combine the derivatives from Step 3 and Step 4. The derivative of \(\ln(x) + x\) is \(\frac{1}{x} + 1\).

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이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Natural Logarithm Properties

Understanding the properties of natural logarithms is essential for simplifying expressions involving ln. Specifically, the property ln(a*b) = ln(a) + ln(b) allows us to break down the logarithm of a product into a sum, which can simplify differentiation.
추천 영상:
05:36
Change of Base Property

Exponential Functions

Exponential functions, such as e^x, have unique properties that make them easier to differentiate. The derivative of e^x is e^x itself, which simplifies calculations significantly when combined with logarithmic functions.
추천 영상:
6:13
Exponential Functions

Basic Differentiation Rules

Familiarity with basic differentiation rules, such as the derivative of a constant and the power rule, is crucial. These rules provide the foundation for finding derivatives without relying on more complex techniques like the Chain Rule or Product Rule.
추천 영상:
04:02
The Power Rule
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