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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
모든 교과서Briggs 3rd EditionCh. 3 - Derivatives문제 3.6.39
3장, 문제 3.6.39

Matching heights A stone is thrown with an initial velocity of 32 ft/s from the edge of a bridge that is 48 ft above the ground. The height of this stone above the ground t seconds after it is thrown is f(t) = −16t²+32t+48 . If a second stone is thrown from the ground, then its height above the ground after t seconds is given by g(t) = −16t²+v0t, where v0 is the initial velocity of the second stone. Determine the value of v0 such that both stones reach the same high point.

검증된 단계별 안내
1
First, identify the maximum height of the first stone. The function f(t) = −16t² + 32t + 48 represents the height of the first stone. To find the maximum height, we need to find the vertex of this quadratic function.
The vertex of a quadratic function ax² + bx + c is given by the formula t = -b/(2a). For f(t), a = -16 and b = 32. Substitute these values into the formula to find the time t at which the first stone reaches its maximum height.
Once you have the time t, substitute it back into the function f(t) to find the maximum height of the first stone.
Now, consider the second stone's height function g(t) = −16t² + v0t. We want this stone to reach the same maximum height as the first stone. Set g(t) equal to the maximum height found from f(t) and solve for v0.
To solve for v0, substitute the time t (found from the vertex calculation) into g(t) and set it equal to the maximum height of the first stone. Solve the resulting equation for v0 to find the initial velocity required for the second stone to reach the same height.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
7m
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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Quadratic Functions

Quadratic functions are polynomial functions of degree two, typically expressed in the form f(t) = at² + bt + c. In this context, both height functions f(t) and g(t) are quadratic, representing the motion of the stones under the influence of gravity. Understanding the properties of these functions, such as their vertex and maximum height, is crucial for determining when both stones reach the same height.
추천 영상:
6:04
Introduction to Polynomial Functions

Vertex of a Parabola

The vertex of a parabola is the highest or lowest point of the graph, depending on its orientation. For the given height functions, the vertex represents the maximum height reached by each stone. The vertex can be found using the formula t = -b/(2a), where a and b are coefficients from the quadratic equation, allowing us to calculate the time at which each stone reaches its peak height.
추천 영상:
7:42
Properties of Parabolas

Initial Velocity and Its Impact

Initial velocity is the speed at which an object is thrown or projected at the start of its motion. In this problem, the initial velocity v0 of the second stone affects its height function g(t) and ultimately determines the time and height at which it reaches its maximum. By equating the maximum heights of both stones, we can solve for v0, ensuring both stones reach the same high point.
추천 영상:
가이드 코스
05:59
Initial Value Problems Example 2
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