Graph each quadratic function. Give the (a) vertex, (b) axis, (c) domain, and (d) range. ƒ(x) = -3 (x - 2)² +1

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Identify the given quadratic function: \(f(x) = -3 (x - 2)^2 + 1\). Notice it is in vertex form, which is \(f(x) = a(x - h)^2 + k\), where \((h, k)\) is the vertex.

Find the vertex by comparing: Here, \(h = 2\) and \(k = 1\), so the vertex is at the point \((2, 1)\).

Determine the axis of symmetry: The axis is the vertical line that passes through the vertex, so it is \(x = 2\).

State the domain of the function: Since this is a quadratic function, the domain is all real numbers, which can be written as \((-\infty, \infty)\).

Find the range by analyzing the vertex and the leading coefficient \(a = -3\): Because \(a\) is negative, the parabola opens downward, so the range includes all \(y\) values less than or equal to the vertex's \(y\)-coordinate, expressed as \((-\infty, 1]\).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Vertex Form of a Quadratic Function

The vertex form of a quadratic function is f(x) = a(x - h)^2 + k, where (h, k) is the vertex of the parabola. This form makes it easy to identify the vertex directly, which is the highest or lowest point depending on the sign of 'a'. In the given function, the vertex is (2, 1).

Axis of Symmetry

The axis of symmetry is a vertical line that passes through the vertex and divides the parabola into two mirror images. Its equation is x = h, where h is the x-coordinate of the vertex. For the function f(x) = -3(x - 2)^2 + 1, the axis of symmetry is x = 2.

Domain and Range of Quadratic Functions

The domain of any quadratic function is all real numbers since you can input any x-value. The range depends on the vertex and the direction the parabola opens. If 'a' is negative, the parabola opens downward, so the range is all y-values less than or equal to the vertex's y-coordinate.

Graph each quadratic function. Give the (a) vertex, (b) axis, (c) domain, and (d) range. ƒ(x) = -3 (x - 2)2 +1