Skip to main content
Ch 33: Wave Optics
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796당신이 사용하는 게 아니라요?교과서 변경
33장, 문제 34

Light from a helium-neon laser (λ = 633 nm) passes through a circular aperture and is observed on a screen 4.0 m behind the aperture. The width of the central maximum is 2.5 cm. What is the diameter (in mm) of the hole?

검증된 단계별 안내
1
Understand the problem: The central maximum in the diffraction pattern is caused by light passing through a circular aperture. The width of the central maximum is related to the aperture diameter by the diffraction formula for a circular aperture.
Use the formula for the angular width of the central maximum in a circular aperture: \( \theta = 1.22 \frac{\lambda}{D} \), where \( \lambda \) is the wavelength of light, \( D \) is the diameter of the aperture, and \( \theta \) is the angular width of the central maximum.
Relate the angular width \( \theta \) to the physical width \( w \) of the central maximum on the screen using the small-angle approximation: \( \theta \approx \frac{w}{2L} \), where \( w \) is the width of the central maximum (2.5 cm) and \( L \) is the distance to the screen (4.0 m).
Combine the two equations: \( \frac{w}{2L} = 1.22 \frac{\lambda}{D} \). Rearrange to solve for \( D \): \( D = 1.22 \frac{\lambda \cdot 2L}{w} \).
Substitute the known values into the equation: \( \lambda = 633 \text{ nm} = 633 \times 10^{-9} \text{ m} \), \( L = 4.0 \text{ m} \), and \( w = 2.5 \text{ cm} = 0.025 \text{ m} \). Simplify the expression to find \( D \) in meters, then convert to millimeters.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Diffraction

Diffraction is the bending of waves around obstacles and the spreading of waves when they pass through small openings. In the context of light, diffraction patterns are created when coherent light, such as that from a laser, encounters an aperture. The resulting pattern on a screen can be analyzed to determine properties of the aperture, such as its size.
추천 영상:

Central Maximum

The central maximum is the brightest and widest part of the diffraction pattern produced when light passes through an aperture. It occurs directly in line with the light source and is flanked by successive dark and bright fringes. The width of the central maximum is influenced by the wavelength of the light and the size of the aperture, making it a key factor in determining the aperture's diameter.
추천 영상:
가이드 코스
06:55
Maximum Load on Floating Board

Wavelength and Aperture Size Relationship

The relationship between the wavelength of light and the size of the aperture is crucial in diffraction phenomena. According to the principles of wave optics, smaller apertures relative to the wavelength produce more pronounced diffraction effects. This relationship can be quantitatively described using formulas that relate the width of the central maximum to the wavelength and the diameter of the aperture, allowing for calculations of the aperture size.
추천 영상:
가이드 코스
03:43
Relationships Between Force, Field, Energy, Potential
관련 실천
교과서 질문

Two 50-μm-wide slits spaced 0.25 mm apart are illuminated by blue laser light with a wavelength of 450 nm. The interference pattern is observed on a screen 2.0 m behind the slits. How many bright fringes are seen in the central maximum that spans the distance between the first missing order on one side and the first missing order on the other side?

137
views
교과서 질문

Infrared light of wavelength 2.5 μm illuminates a 0.20-mm-diameter hole. What is the angle of the first dark fringe in radians? In degrees?

89
views
교과서 질문

Your artist friend is designing an exhibit inspired by circular-aperture diffraction. A pinhole in a red zone is going to be illuminated with a red laser beam of wavelength 670 nm, while a pinhole in a violet zone is going to be illuminated with a violet laser beam of wavelength 410 nm. She wants all the diffraction patterns seen on a distant screen to have the same size. For this to work, what must be the ratio of the red pinhole’s diameter to that of the violet pinhole?

471
views
교과서 질문

FIGURE P33.39 shows the light intensity on a screen 2.5 m behind an aperture. The aperture is illuminated with light of wavelength 620 nm. Is the aperture a single slit or a double slit? Explain.

94
views
교과서 질문

You want to photograph a circular diffraction pattern whose central maximum has a diameter of 1.0 cm. You have a helium-neon laser (λ=633 nm) and a 0.12-mm-diameter pinhole. How far behind the pinhole should you place the screen that's to be photographed?

77
views
교과서 질문

A Michelson interferometer uses red light with a wavelength of 656.45 nm from a hydrogen discharge lamp. How many bright-dark-bright fringe shifts are observed if mirror M₂ is moved exactly 1 cm?

1455
views