A small circular hole 6.00 mm in diameter is cut in the side of a large water tank, 14.0 m below the water level in the tank. The top of the tank is open to the air. Find (a) the speed of efflux of the water and (b) the volume discharged per second.
Ch 12: Fluid Mechanics
12장, 문제 50
A pressure difference of 6.00 × 104 Pa is required to maintain a volume flow rate of 0.800m3/s for a viscous fluid flowing through a section of cylindrical pipe that has radius 0.210 m. What pressure difference is required to maintain the same volume flow rate if the radius of the pipe is decreased to 0.0700 m?
검증된 단계별 안내1
Identify the relationship between pressure difference, volume flow rate, and radius for a viscous fluid in a cylindrical pipe using Poiseuille's Law: \( Q = \frac{\pi \cdot \Delta P \cdot r^4}{8 \cdot \eta \cdot L} \), where \( Q \) is the volume flow rate, \( \Delta P \) is the pressure difference, \( r \) is the radius, \( \eta \) is the dynamic viscosity, and \( L \) is the length of the pipe.
Recognize that the volume flow rate \( Q \) and the dynamic viscosity \( \eta \) remain constant, and the length \( L \) of the pipe is unchanged. Therefore, the relationship between pressure difference and radius can be expressed as \( \Delta P_1 \cdot r_1^4 = \Delta P_2 \cdot r_2^4 \).
Substitute the known values into the equation: \( 6.00 \times 10^4 \text{ Pa} \cdot (0.210 \text{ m})^4 = \Delta P_2 \cdot (0.0700 \text{ m})^4 \).
Solve for the new pressure difference \( \Delta P_2 \) by rearranging the equation: \( \Delta P_2 = \frac{6.00 \times 10^4 \text{ Pa} \cdot (0.210 \text{ m})^4}{(0.0700 \text{ m})^4} \).
Calculate the value of \( \Delta P_2 \) using the given values to find the required pressure difference for the reduced radius.

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이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
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주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Poiseuille's Law
Poiseuille's Law describes the volumetric flow rate of a viscous fluid through a cylindrical pipe. It states that the flow rate is directly proportional to the pressure difference and the fourth power of the pipe's radius, and inversely proportional to the fluid's viscosity and the pipe's length. This relationship highlights the significant impact of the pipe's radius on flow rate.
추천 영상:
가이드 코스
Gauss' Law
Viscosity
Viscosity is a measure of a fluid's resistance to deformation or flow. In the context of fluid dynamics, it quantifies the internal friction within the fluid, affecting how easily it can move through a pipe. Higher viscosity means greater resistance to flow, requiring a larger pressure difference to maintain the same flow rate.
추천 영상:
가이드 코스
Ideal vs Real Fluids
Continuity Equation
The Continuity Equation in fluid dynamics states that the mass flow rate must remain constant from one cross-section of a pipe to another, assuming incompressible flow. This principle implies that if the pipe's radius decreases, the fluid velocity must increase to maintain the same volume flow rate, affecting the required pressure difference.
추천 영상:
가이드 코스
Flow Continuity
관련 실천
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교과서 질문
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