An infinitely long cylindrical conductor has radius and uniform surface charge density . In terms of , what is the magnitude of the electric field produced by the charged cylinder at a distance from its axis? Then, express the result in terms of and show that the electric field outside the cylinder is the same as if all the charge were on the axis.
Ch 22: Gauss' Law
22장, 문제 40b
A very long conducting tube (hollow cylinder) has inner radius and outer radius . It carries charge per unit length , where is a positive constant with units of C/m. A line of charge lies along the axis of the tube. The line of charge has charge per unit length. What is the charge per unit length on (i) the inner surface of the tube and (ii) the outer surface of the tube?
검증된 단계별 안내1
Understand the problem: We have a conducting tube with inner radius A and outer radius B, carrying a charge per unit length +α. A line of charge with the same charge per unit length +α is along the axis of the tube. We need to find the charge per unit length on the inner and outer surfaces of the tube.
Apply Gauss's Law: For a cylindrical Gaussian surface inside the conductor but outside the line of charge, the electric field inside a conductor in electrostatic equilibrium is zero. Therefore, the net charge enclosed by this Gaussian surface must be zero.
Determine the charge on the inner surface: Since the line of charge has a charge per unit length +α, the inner surface of the tube must have a charge per unit length of -α to ensure the electric field inside the conductor is zero.
Calculate the total charge on the tube: The tube itself has a charge per unit length of +α. Since the inner surface has a charge per unit length of -α, the outer surface must have a charge per unit length that accounts for the total charge of the tube.
Find the charge on the outer surface: The charge per unit length on the outer surface of the tube is the sum of the tube's charge per unit length and the negative of the inner surface charge per unit length, which results in +2α.

비슷한 문제에 대한 검증된 영상 답변:
이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
6m도움이 되었나요?
주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Gauss's Law
Gauss's Law relates the electric flux through a closed surface to the charge enclosed by that surface. It is essential for calculating electric fields in symmetric charge distributions, such as cylindrical geometries. For a long conducting tube, Gauss's Law helps determine how charge distributes on the inner and outer surfaces based on the symmetry and enclosed charge.
추천 영상:
가이드 코스
Gauss' Law
Conductors in Electrostatic Equilibrium
In electrostatic equilibrium, conductors have no electric field inside them, and any excess charge resides on their surface. This principle is crucial for understanding how charges distribute on the inner and outer surfaces of a conducting tube. The inner surface will adjust to neutralize the field from the line charge, while the outer surface will carry any remaining charge.
추천 영상:
가이드 코스
Electric Fields in Conductors
Charge Distribution on Cylindrical Surfaces
Charge distribution on cylindrical surfaces depends on the geometry and symmetry of the system. For a hollow conducting cylinder, the charge per unit length on the inner surface will counteract the line charge along the axis, while the outer surface will carry the net charge per unit length. Understanding this distribution is key to solving the problem of charge per unit length on each surface.
추천 영상:
가이드 코스
Equipotential Surfaces
관련 실천
교과서 질문
4487
views
1
rank
교과서 질문
An infinitely long cylindrical conductor has radius and uniform surface charge density . In terms of and , what is the charge per unit length for the cylinder?
2450
views
1
rank
교과서 질문
A very long conducting tube (hollow cylinder) has inner radius and outer radius . It carries charge per unit length , where is a positive constant with units of C/m. A line of charge lies along the axis of the tube. The line of charge has charge per unit length. Calculate the electric field in terms of and the distance from the axis of the tube for (i) ; (ii) ; (iii) . Show your results in a graph of as a function of .
2382
views
1
rank
