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Ch 22: Gauss' Law
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610당신이 사용하는 게 아니라요?교과서 변경
22장, 문제 40b

A very long conducting tube (hollow cylinder) has inner radius AA and outer radius bb. It carries charge per unit length +α, where αα is a positive constant with units of C/m. A line of charge lies along the axis of the tube. The line of charge has charge per unit length. What is the charge per unit length on (i) the inner surface of the tube and (ii) the outer surface of the tube?

검증된 단계별 안내
1
Understand the problem: We have a conducting tube with inner radius A and outer radius B, carrying a charge per unit length +α. A line of charge with the same charge per unit length +α is along the axis of the tube. We need to find the charge per unit length on the inner and outer surfaces of the tube.
Apply Gauss's Law: For a cylindrical Gaussian surface inside the conductor but outside the line of charge, the electric field inside a conductor in electrostatic equilibrium is zero. Therefore, the net charge enclosed by this Gaussian surface must be zero.
Determine the charge on the inner surface: Since the line of charge has a charge per unit length +α, the inner surface of the tube must have a charge per unit length of -α to ensure the electric field inside the conductor is zero.
Calculate the total charge on the tube: The tube itself has a charge per unit length of +α. Since the inner surface has a charge per unit length of -α, the outer surface must have a charge per unit length that accounts for the total charge of the tube.
Find the charge on the outer surface: The charge per unit length on the outer surface of the tube is the sum of the tube's charge per unit length and the negative of the inner surface charge per unit length, which results in +2α.

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이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
6m
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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Gauss's Law

Gauss's Law relates the electric flux through a closed surface to the charge enclosed by that surface. It is essential for calculating electric fields in symmetric charge distributions, such as cylindrical geometries. For a long conducting tube, Gauss's Law helps determine how charge distributes on the inner and outer surfaces based on the symmetry and enclosed charge.
추천 영상:

Conductors in Electrostatic Equilibrium

In electrostatic equilibrium, conductors have no electric field inside them, and any excess charge resides on their surface. This principle is crucial for understanding how charges distribute on the inner and outer surfaces of a conducting tube. The inner surface will adjust to neutralize the field from the line charge, while the outer surface will carry any remaining charge.
추천 영상:
가이드 코스
07:43
Electric Fields in Conductors

Charge Distribution on Cylindrical Surfaces

Charge distribution on cylindrical surfaces depends on the geometry and symmetry of the system. For a hollow conducting cylinder, the charge per unit length on the inner surface will counteract the line charge along the axis, while the outer surface will carry the net charge per unit length. Understanding this distribution is key to solving the problem of charge per unit length on each surface.
추천 영상:
가이드 코스
09:18
Equipotential Surfaces