If an enterocyte contains 1.20 g of palmitic acid (C16:0; molecular weight = 256.4 g·mol⁻¹) and palmitic acid will occupy only one fatty acid position per triglyceride (i.e., each TG incorporates exactly one palmitic acid and the other two positions are filled by other available fatty acids), how many triglyceride molecules can be formed from the available palmitic acid? (Provide molecules and molar amount.)

• A. Approximately 1.20 mol, ≈ 7.23 × 10^23 molecules, due to one-to-one conversion from grams to moles when using palmitic acid as the sole fatty acid source.
• B. Approximately 0.000468 mol, ≈ 2.82 × 10^20 molecules, because only 10% of dietary palmitic acid is available for triglyceride synthesis after oxidation in enterocytes.
• C. Approximately 0.0140 mol, ≈ 8.43 × 10^21 molecules, because palmitic acid will occupy all three positions of each triglyceride by simple ester exchange in enterocytes.
• D. Approximately 0.00468 mol, ≈ 2.82 × 10^21 triglyceride molecules.

Answer: (D)