A chemist observes a doublet with a coupling constant (J) value of 6.6 Hz and a chemical shift (δ) about 3.00 ppm in the NMR spectrum of a compound measured using a 60.0-MHz spectrometer.
(i) If the spectrum is taken using a 300-MHz spectrometer, what would the chemical shift (δ) be?
(ii) What would the splitting value J be if the spectrum is taken using a 300-MHz spectrometer?
(iii) How many Hz from the TMS peak is this signal in the 60.0-MHz spectrum? In the 300-MHz spectrum?

• A. (i): 15 ppm
  
  (ii): 33 Hz
  
  (iii): 60 Hz downfield from TMS signal in the 60.0 MHz spectrum.
  300 Hz downfield from TMS signal in the 300 MHz spectrum.
• B. (i): 0.60 ppm
  
  (ii): 1.3 Hz
  
  (iii): 60 Hz downfield from TMS signal in the 60.0 MHz spectrum.
  300 Hz downfield from TMS signal in the 300 MHz spectrum.
• C. (i): 15 ppm
  
  (ii): 33 Hz
  
  (iii): 180 Hz downfield from TMS signal in the 60.0 MHz spectrum.
  900 Hz downfield from TMS signal in the 300 MHz spectrum.
• D. (i): 3.0 ppm
  
  (ii): 6.6 Hz
  
  (iii): 180 Hz downfield from TMS signal in the 60.0 MHz spectrum.
  900 Hz downfield from TMS signal in the 300 MHz spectrum.

Answer: (D)