The compound below contains alternating double bonds and has 14 π electrons (4n + 2 with n = 3), therefore, it is aromatic. Is this statement true or false? Explain.

• A. True. The compound has all the conditions for it to be aromatic.
• B. True. The compound is aromatic because all the electrons are delocalized.
• C. False. Only fully conjugated monocyclic hydrocarbons with less than nine carbons can be aromatic.
• D. False. The compound is not aromatic because it is not planar, and the π-orbitals will not be lined up.

Answer: (D)