-4t-1-where-x-is-in-meters-and-t-is-in-seconds-what-is-its-acceleration-at-t-2-s

Question

A cart moves along a track with position x(t)=2t3−9t2+4t+1x(t) = $$2t^3$$ - $$9t^2 + 4t + 1$$, where xx is in meters and tt is in seconds. What is its acceleration at t=2t = 2 s	ext{s}?

Accepted Answer

66 m/s2	ext{m/s}^2

Answer

44 m/s2	ext{m/s}^2

Answer

1212 m/s2	ext{m/s}^2

Answer

−6-6 m/s2	ext{m/s}^2

A cart moves along a track with position x(t)=2t3−9t2+4t+1x(t) = 2t^3 - 9t^2 + 4t + 1, where xx is in meters and tt is in seconds. What is its acceleration at t=2t = 2 s\(\text{s}\)?

A cart moves along a track with position $x (t) = 2 t^{3} - 9 t^{2} + 4 t + 1$ , where $x$ is in meters and $t$ is in seconds. What is its acceleration at $t equals 2$ $s$ ?