Physics with Calculus
x(t)=23t3+6t2−2t+3x(t)=\(\frac\)23t^3+6t^2-2t+3
x(t)=23t3+3t2−2t+3x(t)=\(\frac\)23t^3+3t^2-2t+3
x(t)=23t3+3t2+2t+3x(t)=\(\frac\)23t^3+3t^2+2t+3
x(t)=2t3+3t2−2t+3x(t) = 2t^3 + 3t^2 - 2t + 3