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Question

A luggage cart with mass $m$ is placed on an airport's moving walkway moving at speed $v$ . The kinetic friction coefficient between the cart and walkway is $\mu_{k}$ . Over time $t$ , the cart stops moving relative to the walkway, traveling distance $d=\frac12\frac{v^2}{\mu_{k}g}$ . How much of the work done by the walkway's motor is used against friction and how much to accelerate the luggage?

Diagram showing two luggage carts on a moving walkway with variables for mass, distance, and speed.

Accepted Answer

$W_{f r i c t i o n} = \frac{1}{2} m v^{2}; W_{a c c e l e r a t i o n} = \frac{1}{2} m v^{2}$

Answer

$W_{friction}=\frac{1}{4}mv^2;W_{acceleration}=\frac{1}{4}mv^2$

Answer

$W_{friction}=\frac{1}{4}mv^2;W_{acceleration}=\frac{1}{4}mv^2$

Answer

$W_{friction}=\frac{1}{4}mv^2;W_{acceleration}=\frac{1}{4}mv^2$