graph-the-following-function-consider-only-one-periody-sec-x-32

Question

Graph the following function. Consider only one period.

$y=\sec\left(x+\frac{3\pi}{2}\right)$

Accepted Answer

Graph of y=sec(x+3π/2) showing one period with vertical asymptotes.

Answer

Graph of y=sec(x+3π/2) showing one period with vertical asymptotes.

Answer

Graph of y=sec(x+3π/2) showing one period with vertical asymptotes.

Answer

Graph of y=sec(x+3π/2) showing one period with vertical asymptotes.

Graph the following function. Consider only one period.y=sec(x+3π2)y=\sec\left(x+\frac{3\pi}{2}\right)y=sec(x+23π)