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Chemical Thermodynamics: Gibbs Free Energy
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Chemical Thermodynamics: Gibbs Free Energy
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6. Chemical Equilibrium / Chemical Thermodynamics: Gibbs Free Energy / Problem 3
Problem 3
Given ΔG° = -40 kJ/mol and R = 8.314 J/mol·K, calculate the equilibrium constant K at 298 K.
A
K = 3.0 x 10
4
B
K = 5.0 x 10
5
C
K = 2.5 x 10
3
D
K = 1.2 x 10
7
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