Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations.{x=y2−3x=y2−3y\(\left\)\{\(\begin{array}{l}\)x=y^2-3\\ x=y^2-3y\(\end{array}\]\right\). 674views
Textbook QuestionFind the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. {x=(y+2)2−1(x−2)2+(y+2)2=1\(\begin{cases}\)x = (y + 2)^2 - 1 \\(x - 2)^2 + (y + 2)^2 = 1\(\end{cases}\){x=(y+2)2−1(x−2)2+(y+2)2=1883views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = - 4x863views
Multiple ChoiceGraph the parabola −4(y+1)=(x+1)2-4\(\left\)(y+1\(\right\))=\(\left\)(x+1\(\right\))^2−4(y+1)=(x+1)2, and find the focus point and directrix line.778views
Multiple ChoiceGraph the parabola 8(x+1)=(y−2)28\(\left\)(x+1\(\right\))=\(\left\)(y-2\(\right\))^28(x+1)=(y−2)2 , and find the focus point and directrix line.737views
Multiple ChoiceIf a parabola has the focus at (2,4)\(\left\)(2,4\(\right\))(2,4) and a directrix line x=−4x=-4x=−4 , find the standard equation for the parabola.604views1rank