When benzene 1C6H62 reacts with bromine 1Br22, bromobenzene
1C6H5Br2 is obtained:
C6H6 + Br2¡C6H5Br + HBr
(a) When 30.0 g of benzene reacts with 65.0 g of bromine, what
is the theoretical yield of bromobenzene?
Play a video:
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?
Master Limiting Reagent with a bite sized video explanation from Jules Bruno