An aqueous solution is 23.0% acetic acid (CH₃COOH) by mass. Calculate the mole fraction of the solute and the molality of the solution.

• A. mole fraction = 14.5, molality = 230 m
• B. mole fraction = 0.0690, molality = 13.8 m
• C. mole fraction = 0.0645, molality = 3.83 m
• D. mole fraction = 0.0823, molality = 4.97 m

Answer: (D)