Find the missing species in the following nuclear equation and calculate the energy change per mole of Ar-34: 
³⁴₁₈Ar + _____ → ³¹₁₆S + ⁴₂He
 
m_Ar-34 = 33.9802 amu
m_S-31 = 30.9795 amu
m_He-4 = 4.0026 amu 

• A. Missing species = ¹₀nEnergy change = 6.0211 x 10¹¹ J/mol
• B. Missing species = ¹₀HEnergy change = 6.0211 x 10²³ J/mol
• C. Missing species = ⁴₂HeEnergy change = 9.9984 x 10^-13 J/mol
• D. Missing species = ¹₁HEnergy change = 1.1125 x 10^-29 J/mol

Answer: (A)