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Ka and Kb
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Ka and Kb
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17. Acid and Base Equilibrium / Ka and Kb / Problem 6
Problem 6
Arrange the following in decreasing base strength
H
3
PO
4
(Ka = 7.1x10
-3
)
HNO
3
(Ka = 2.4x10
1
)
H
2
S (Ka = 1.1x10
-7
)
HClO (Ka = 2.9x10
-8
)
A
HNO
3
> H
3
PO
4
> H
2
S > HClO
B
HClO > H
2
S > H
3
PO
4
> HNO
3
C
H
3
PO
4
> HNO
3
> HClO > H
2
S
D
H
2
S > H
3
PO
4
> HNO
3
> HClO
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