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Ch. 17 - Recombinant DNA Technology
Klug - Essentials of Genetics 10th Edition
Klug10th EditionEssentials of GeneticsISBN: 9780135588789Not the one you use?Change textbook
Chapter 17, Problem 12

If you performed a PCR experiment starting with only one copy of double-stranded DNA, approximately how many DNA molecules would be present in the reaction tube after 15 cycles of amplification?

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Understand that PCR (Polymerase Chain Reaction) amplifies DNA by doubling the number of DNA molecules each cycle, assuming 100% efficiency.
Identify the initial number of DNA molecules, which in this case is 1 double-stranded DNA molecule.
Recognize that after each cycle, the number of DNA molecules doubles, so the number of molecules after n cycles is given by the formula: \(N = N_0 \times 2^n\), where \(N_0\) is the initial number of molecules and \(n\) is the number of cycles.
Substitute the given values into the formula: \(N_0 = 1\) and \(n = 15\), so the expression becomes \(N = 1 \times 2^{15}\).
Calculate the value of \$2^{15}$ to find the approximate number of DNA molecules after 15 cycles.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Polymerase Chain Reaction (PCR) Process

PCR is a technique used to amplify specific DNA sequences exponentially by cycling through denaturation, annealing, and extension steps. Each cycle ideally doubles the number of DNA molecules, allowing for rapid multiplication from a small initial amount.
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Exponential Amplification

In PCR, the number of DNA molecules doubles with each cycle, leading to exponential growth. Starting with one DNA molecule, after n cycles, the number of molecules is approximately 2^n, assuming 100% efficiency.

Initial Template Quantity and Cycle Number

The starting amount of DNA and the number of PCR cycles determine the final quantity of DNA. Beginning with a single double-stranded DNA molecule and performing 15 cycles results in roughly 2^15 DNA molecules, illustrating the power of PCR amplification.
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