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Ch. 3 - Mendelian Genetics
Klug - Essentials of Genetics 10th Edition
Klug10th EditionEssentials of GeneticsISBN: 9780135588789Not the one you use?Change textbook
Chapter 3, Problem 14

Mendel crossed peas having round green seeds with peas having wrinkled yellow seeds. All F₁ plants had seeds that were round and yellow. Predict the results of testcrossing these F₁ plants.

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1
Identify the traits and their dominance relationships: Round (R) is dominant over wrinkled (r), and yellow (Y) is dominant over green (y).
Determine the genotype of the F₁ plants. Since the parents were round green (R_yy) and wrinkled yellow (rrY_), and all F₁ were round yellow, the F₁ genotype must be heterozygous for both traits: RrYy.
Understand that a testcross involves crossing the F₁ heterozygote (RrYy) with a homozygous recessive individual for both traits (rryy).
Set up a Punnett square for the testcross, where the F₁ parent can produce four types of gametes: RY, Ry, rY, and ry, and the testcross parent produces only ry gametes.
Predict the phenotypic ratios of the offspring by combining each F₁ gamete with the testcross gamete, resulting in four phenotypic classes: round yellow, round green, wrinkled yellow, and wrinkled green, each with equal probability.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Mendelian Inheritance and Dominance

Mendelian inheritance describes how traits are passed from parents to offspring through dominant and recessive alleles. In this case, round seed shape and yellow seed color are dominant traits, while wrinkled and green are recessive. The F₁ generation shows dominant phenotypes because they inherit one dominant allele from each parent.
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Variations on Dominance

Testcross

A testcross involves crossing an individual with a dominant phenotype but unknown genotype with a homozygous recessive individual. This helps reveal the genotype of the dominant individual by analyzing the phenotypes of the offspring, distinguishing between homozygous dominant and heterozygous genotypes.

Independent Assortment and Dihybrid Cross

Independent assortment states that alleles of different genes segregate independently during gamete formation. Crossing round yellow (heterozygous for both traits) peas with wrinkled green (homozygous recessive) peas results in a 1:1:1:1 phenotypic ratio in offspring, reflecting all combinations of seed shape and color.
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Gamete Genetics and Independent Assortment
Related Practice
Textbook Question

In Drosophila, gray body color is dominant to ebony body color, while long wings are dominant to vestigial wings. Assuming that the P₁ individuals are homozygous, work the following crosses through the F₂ generation, and determine the genotypic and phenotypic ratios for each generation.

gray, vestigial x ebony, long

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Textbook Question

In Drosophila, gray body color is dominant to ebony body color, while long wings are dominant to vestigial wings. Assuming that the P₁ individuals are homozygous, work the following crosses through the F₂ generation, and determine the genotypic and phenotypic ratios for each generation.

gray, long x gray, vestigial.

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Textbook Question

How many different types of gametes can be formed by individuals of the following genotypes:

(a) AaBb

(b) AaBB

(c) AaBbCc

(d) AaBBcc

(e) AaBbcc

(f) AaBbCcDdEe

What are the gametes in each case?

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Textbook Question

The following are F₂ results of two of Mendel's monohybrid crosses.

For each cross, state a null hypothesis to be tested using x² analysis. Calculate the x² value and determine the p value for both. Interpret the p-values. Can the deviation in each case be attributed to chance or not? Which of the two crosses shows a greater amount of deviation?

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Textbook Question

In assessing data that fell into two phenotypic classes, a geneticist observed values of 250:150. She decided to perform a χ\chi² analysis by using the following two different null hypotheses:

(a) the data fit a 3:1 ratio, and

(b) the data fit a 1:1 ratio.

Calculate the χ\chi ² values for each hypothesis. What can be concluded about each hypothesis?

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Textbook Question

The basis for rejecting any null hypothesis is arbitrary. The researcher can set more or less stringent standards by deciding to raise or lower the p value used to reject or not reject the hypothesis. In the case of the chi-square analysis of genetic crosses, would the use of a standard of p = 0.10 be more or less stringent about not rejecting the null hypothesis? Explain.

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