Using each of the following electron arrangements, give the formulas for the cation and anion that form, the formula for the compound they form, and its name.

Question

Table displaying electron arrangements, cations, anions, compound formulas, and compound names for ionic compounds.

Accepted Answer

Hello. In this problem, we are asked for the given electron arrangements. 2881 and 286, identify the symbol for the caine. The symbol for the, an the formula for the ionic compound they form and the name of the ionic compound. Let's begin by looking at the periodic table of elements, electron arrangements. Then refers to the filling of the S P N D orbitals. We begin with the first electron arrangement where we have a two. That means then we are beginning by filling period one where we're filling the one S orbitals. So we have 12 across period one, we're now at helium. The next number is in eight. So we are going to be filling the two S and the two P orbitals in period two, we'll count across 812345678. This then gets us to neon. The next number is in eight. We will be filling the three S and the three P orbitals in period three, we will count eight across that gets us to argon and then we have one. So the one then will go in period four group one A, the LMA. Then that is in period four group one A is potassium, we will do the same thing. Then for the other electron arrangement, the periodic table has been cleared, except for the placement of our one element potassium, we are going to do the same thing. Then for the next electron arrangement, our first number then is two. So we're gonna be filling the one S orbitals. So in period one, we have 12 that gets us to helium. Then we have an eight, we're gonna be filling the two S and two P orbitals in period two. So we're gonna count eight across 12345678. And that gets us to neon. Then we're in period three, we're gonna be filling the three S and then the three P orbitals. So we're gonna count across that puts us in period three group six A, the alma that appears in period three, group six A is sulfur. So our two elements are potassium and sulfur, which makes sense, right? We need to have a metal, which is potassium and we need to have a nonmetal which is sulfur. Potassium then is in group one A as we see, it has one valence electron, it will lose that one valence electron then to become like argon and it will form a ion with a plus charge sulfur. Then is in group six A, it needs two or more electrons to get to an Octa. And so it will gain two electrons form ions with a two minus charge. We can take our two ions, potassium ion and sulfide iron. And then we're gonna do the crossing method to come up with the formula for the ionic compound. So this would be a one and this would be a two. So our superscripts now become subscripts. The chemical formula for ionic compound is K subscript two S. When we name it, then the metal gets named first and it gets the full name of the metal. So this is potassium and the nonmetal gets named second, it has the first syllable of its name and then the ID E ending. So it would be called sulfide. So the name of the a a compound is potassium sulfide. So this then corresponds with answer B. Thanks for watching. Hope this helped.

Using each of the following electron arrangements, give the formulas for the cation and anion that form, the formula for the compound they form, and its name.

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Key Concepts

Electron Configuration

Ionic Compounds

Nomenclature of Ionic Compounds