Consider the following reaction:
•CH(CH₃)₂ + HF → (CH₃)₂CH₂ + F•
The activation energy and the heat of reaction (ΔH°) of its reverse reaction are 26.1 kJ/mol (6.24 kcal/mol) and −157 kJ/mol (−37.5 kcal/mol), respectively. Determine the activation energy and the heat of reaction (ΔH°) for the forward reaction.

• A. E_{a, reverse} = 183 kJ/mol (43.7 kcal/mol)ΔH°_reverse = 157 kJ/mol (37.5 kcal/mol)
• B. E_{a, reverse} = −26.1 kJ/mol (−6.24 kcal/mol)ΔH°_reverse = 157 kJ/mol (37.5 kcal/mol)
• C. E_{a, reverse} = −26.1 kJ/mol (−6.24 kcal/mol)ΔH°_reverse = −157 kJ/mol (−37.5 kcal/mol)
• D. E_{a, reverse} = −183 kJ/mol (−43.7 kcal/mol)ΔH°_reverse = 157 kJ/mol (37.5 kcal/mol)

Answer: (A)