Determine the highest occupied molecular orbital (HOMO) and lowest unoccupied molecular orbital (LUMO) for the given allylic cation and allylic anion.

• A. HOMO: Allylic cation: Ψ₂; Allylic anion: Ψ₁
  LUMO: Allylic cation: Ψ₁; Allylic anion: Ψ₃
• B. HOMO: Allylic cation: Ψ₁; Allylic anion: Ψ₂
  LUMO: Allylic cation: Ψ₂; Allylic anion: Ψ₃
• C. HOMO: Allylic cation: Ψ₂; Allylic anion: Ψ₃
  LUMO: Allylic cation: Ψ₁; Allylic anion: Ψ₂
• D. HOMO: Allylic cation: Ψ₃; Allylic anion: Ψ₂
  LUMO: Allylic cation: Ψ₂; Allylic anion: Ψ₁

Answer: (B)