Describe how the IR spectrum of the products would be used to differentiate them from the reactants in the following three reactions.

• A. (a) Reactant = broad peak near 3300 cm^–1, product = strong peak near 1715 cm^–1(b) Reactant = broad peak near 3000 cm^–1, product = Missing peak near 3000 cm^–1(c) Reactant = strong peak near 1715 cm^–1, product = strong peak near 3300 cm^–1
• B. (a) Reactant = broad peak near 1700 cm^–1, product = strong peak near 3000 cm^–1(b) Reactant = broad peak near 3000 cm^–1, product = Missing peak near 3000 cm^–1(c) Reactant = strong peak near 3300 cm^–1, product = strong peak near 1715 cm^–1
• C. (a) Reactant = broad peak near 1300 cm^–1, product = strong peak near 1715 cm^–1(b) Reactant = broad peak near 1600 cm^–1, product = Strong peak near 3300 cm^–1(c) Reactant = strong peak near 3300 cm^–1, product = strong peak near 1715 cm^–1
• D. (a) Reactant = broad peak near 3000 cm^–1, product = strong peak near 1715 cm^–1(b) Reactant = broad peak near 1600 cm^–1, product = Broad peak near 1100 cm^–1(c) Reactant = strong peak near 1750 cm^–1, product = strong peak near 3500 cm^–1

Answer: (A)