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Oxidation, Reduction, and Reactions of Hydrocarbons III: Alkanes, Alkenes, and Alkynes

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Oxidation of Hydrocarbons

Baeyer's Test

Baeyer's test is a qualitative method in organic chemistry used to detect the presence of unsaturation (double or triple bonds) in organic compounds. The test utilizes an alkaline solution of potassium permanganate (KMnO4), a powerful oxidizing agent.

  • Principle: KMnO4 reacts with double or triple bonds, causing the solution to change color from purplish-pink to brown due to the formation of manganese(IV) oxide (MnO2).

  • Reaction: The double bond is replaced by hydroxyl groups (OH), resulting in syn-hydroxylation.

  • Limitations: The test does not work on alkanes or aromatic compounds. Easily oxidized compounds (e.g., aldehydes, impurities in alcohols/alkanes) may give false positives.

Example Reaction:

  • Alkene + KMnO4 + H2O → Glycol (1,2-diol) + MnO2 (brown solid)

  • Alkyne + KMnO4 + H2O → Diketone or carboxylic acids + MnO2

Equation:

Oxidation of Alkenes: Syn-Hydroxylation

Potassium permanganate oxidizes alkenes to produce 1,2-diols (glycols) via syn-hydroxylation, where both hydroxyl groups add to the same side of the double bond.

  • Reagent: Cold, dilute, and basic KMnO4 is used to limit further oxidation.

  • Mechanism: The reaction proceeds through a cyclic manganate ester intermediate.

  • Product: 1,2-ethanediol (ethylene glycol) from ethene.

Equation:

Oxidative Cleavage of Alkenes and Alkynes

Strong oxidizing agents (hot, concentrated KMnO4 or ozone) can cleave double or triple bonds, breaking the unsaturation and forming highly oxidized products.

  • Hot basic KMnO4: Cleaves alkenes to carboxylates, ketones, or CO2 depending on substitution.

  • Ozonolysis: Cleavage with ozone followed by zinc/acetic acid workup yields aldehydes, ketones, or formaldehyde.

Product Table:

Type of Carbon

KMnO4 Cleavage Product

Ozonolysis Product

Unsubstituted

CO2

Formaldehyde

Monosubstituted

Carboxylate

Aldehyde

Disubstituted

Ketone

Ketone

Example:

  • (Acetate ion)

Ozonolysis of Alkenes and Alkynes

Ozonolysis is a method for cleaving double or triple bonds using ozone (O3), followed by reduction with zinc in acetic acid. This produces carbonyl compounds (aldehydes, ketones, or carboxylic acids).

  • Alkenes: Ozone reacts to form unstable ozonides, which are reduced to carbonyl compounds.

  • Alkynes: Internal alkynes yield two carboxylic acids; terminal alkynes yield a carboxylic acid and CO2.

Equation:

  • (internal)

  • (terminal)

Reduction of Alkynes

Complete Reduction to Alkanes

Alkynes can be fully reduced to alkanes by catalytic hydrogenation using a metal catalyst such as palladium on carbon (Pd/C).

  • Reaction: Addition of H2 over Pd/C converts alkynes to alkanes.

  • Equation:

Partial Reduction: Formation of Cis- and Trans-Alkenes

  • Cis-Alkene Formation (Lindlar's Catalyst): Hydrogenation using Lindlar's catalyst (deactivated palladium on calcium carbonate) produces cis-alkenes via syn addition.

  • Trans-Alkene Formation (Dissolving Metal Reduction): Sodium or lithium in liquid ammonia reduces alkynes to trans-alkenes via a radical anion intermediate.

Equations:

Example:

  • 3-hexyne + Lindlar's catalyst + H2 → cis-3-hexene

  • 3-hexyne + Na/NH3 → trans-3-hexene

Acetylide Ions

Formation and Properties

Terminal alkynes can be deprotonated by strong bases to form acetylide ions, which are strong carbon nucleophiles.

  • Acidity: Alkynes are more acidic than alkenes and alkanes due to increased s-character of the sp-hybridized carbon.

  • Base Used: Sodium amide (NaNH2) is commonly used to deprotonate terminal alkynes.

Acidity Table (pKa values):

Compound

pKa

HCl

-8.0

CH3COOH

4.76

H2O

15.7

HC≡CH

24

HC=CH

44

CH3CH3

50

Equation:

Reactions of Acetylide Ions

Acetylide ions act as nucleophiles and react with alkyl halides to form new carbon-carbon bonds via alkylation.

  • Alkylation: Reaction with 1° alkyl halides (RCH2X) leads to chain extension.

  • Elimination: 2° and 3° alkyl halides undergo elimination (E2 mechanism) due to steric hindrance.

Equation:

Example:

  • 1-pentyne + NaNH2 → acetylide ion; acetylide ion + 1° alkyl halide → extended alkyne

Hydrocarbon Combustion

Complete Combustion

Alkanes undergo combustion in the presence of oxygen to produce carbon dioxide and water, releasing energy.

  • Equation:

  • Every C-H and C-C bond in the starting material is converted to a C-O bond in the product.

Incomplete Combustion

In the absence of sufficient oxygen, incomplete combustion occurs, forming carbon monoxide (CO) and water.

  • General Equation:

  • For methane:

  • Oxidation of saturated hydrocarbons is the basis for their use as energy sources for heat.

Summary Table

Topic

Key Reagents/Conditions

Main Products

Oxidation (Baeyer's Test)

KMnO4 (alkaline)

Diols, brown MnO2

Oxidative Cleavage

Hot KMnO4, Ozone/Zn/HOAc

Carboxylates, aldehydes, ketones, CO2

Reduction

Pd/C, Lindlar's catalyst, Na/NH3

Alkanes, cis-alkenes, trans-alkenes

Acetylide Ion Formation

NaNH2, LDA, tBuLi

Acetylide ions

Combustion

O2 (excess or limited)

CO2, H2O, CO

Knowledge Check Examples

  • Which reaction conditions best convert 3-hexyne to cis-3-hexene? Answer: Lindlar's catalyst and H2

  • Classify the following transformation as oxidation or reduction: Alkene to alkane: Reduction Aldehyde to alcohol: Reduction

References

  • Carey, F.A. (2008) Organic Chemistry 7th ed. McGraw Hill

  • McMurry, J. (2008) Organic Chemistry 7th ed. Thomson Brooks Cole

  • Bruice, P.Y. (2017) Organic Chemistry 8th ed. Prentice Hall International

  • Brown W.H., Poon, T. (2016) Introduction to Organic Chemistry 6th ed. Wiley

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