BackOxidation, Reduction, and Reactions of Hydrocarbons III: Alkanes, Alkenes, and Alkynes
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Oxidation of Hydrocarbons
Baeyer's Test
Baeyer's test is a qualitative method in organic chemistry used to detect the presence of unsaturation (double or triple bonds) in organic compounds. The test utilizes an alkaline solution of potassium permanganate (KMnO4), a powerful oxidizing agent.
Principle: KMnO4 reacts with double or triple bonds, causing the solution to change color from purplish-pink to brown due to the formation of manganese(IV) oxide (MnO2).
Reaction: The double bond is replaced by hydroxyl groups (OH), resulting in syn-hydroxylation.
Limitations: The test does not work on alkanes or aromatic compounds. Easily oxidized compounds (e.g., aldehydes, impurities in alcohols/alkanes) may give false positives.
Example Reaction:
Alkene + KMnO4 + H2O → Glycol (1,2-diol) + MnO2 (brown solid)
Alkyne + KMnO4 + H2O → Diketone or carboxylic acids + MnO2
Equation:
Oxidation of Alkenes: Syn-Hydroxylation
Potassium permanganate oxidizes alkenes to produce 1,2-diols (glycols) via syn-hydroxylation, where both hydroxyl groups add to the same side of the double bond.
Reagent: Cold, dilute, and basic KMnO4 is used to limit further oxidation.
Mechanism: The reaction proceeds through a cyclic manganate ester intermediate.
Product: 1,2-ethanediol (ethylene glycol) from ethene.
Equation:
Oxidative Cleavage of Alkenes and Alkynes
Strong oxidizing agents (hot, concentrated KMnO4 or ozone) can cleave double or triple bonds, breaking the unsaturation and forming highly oxidized products.
Hot basic KMnO4: Cleaves alkenes to carboxylates, ketones, or CO2 depending on substitution.
Ozonolysis: Cleavage with ozone followed by zinc/acetic acid workup yields aldehydes, ketones, or formaldehyde.
Product Table:
Type of Carbon | KMnO4 Cleavage Product | Ozonolysis Product |
|---|---|---|
Unsubstituted | CO2 | Formaldehyde |
Monosubstituted | Carboxylate | Aldehyde |
Disubstituted | Ketone | Ketone |
Example:
(Acetate ion)
Ozonolysis of Alkenes and Alkynes
Ozonolysis is a method for cleaving double or triple bonds using ozone (O3), followed by reduction with zinc in acetic acid. This produces carbonyl compounds (aldehydes, ketones, or carboxylic acids).
Alkenes: Ozone reacts to form unstable ozonides, which are reduced to carbonyl compounds.
Alkynes: Internal alkynes yield two carboxylic acids; terminal alkynes yield a carboxylic acid and CO2.
Equation:
(internal)
(terminal)
Reduction of Alkynes
Complete Reduction to Alkanes
Alkynes can be fully reduced to alkanes by catalytic hydrogenation using a metal catalyst such as palladium on carbon (Pd/C).
Reaction: Addition of H2 over Pd/C converts alkynes to alkanes.
Equation:
Partial Reduction: Formation of Cis- and Trans-Alkenes
Cis-Alkene Formation (Lindlar's Catalyst): Hydrogenation using Lindlar's catalyst (deactivated palladium on calcium carbonate) produces cis-alkenes via syn addition.
Trans-Alkene Formation (Dissolving Metal Reduction): Sodium or lithium in liquid ammonia reduces alkynes to trans-alkenes via a radical anion intermediate.
Equations:
Example:
3-hexyne + Lindlar's catalyst + H2 → cis-3-hexene
3-hexyne + Na/NH3 → trans-3-hexene
Acetylide Ions
Formation and Properties
Terminal alkynes can be deprotonated by strong bases to form acetylide ions, which are strong carbon nucleophiles.
Acidity: Alkynes are more acidic than alkenes and alkanes due to increased s-character of the sp-hybridized carbon.
Base Used: Sodium amide (NaNH2) is commonly used to deprotonate terminal alkynes.
Acidity Table (pKa values):
Compound | pKa |
|---|---|
HCl | -8.0 |
CH3COOH | 4.76 |
H2O | 15.7 |
HC≡CH | 24 |
HC=CH | 44 |
CH3CH3 | 50 |
Equation:
Reactions of Acetylide Ions
Acetylide ions act as nucleophiles and react with alkyl halides to form new carbon-carbon bonds via alkylation.
Alkylation: Reaction with 1° alkyl halides (RCH2X) leads to chain extension.
Elimination: 2° and 3° alkyl halides undergo elimination (E2 mechanism) due to steric hindrance.
Equation:
Example:
1-pentyne + NaNH2 → acetylide ion; acetylide ion + 1° alkyl halide → extended alkyne
Hydrocarbon Combustion
Complete Combustion
Alkanes undergo combustion in the presence of oxygen to produce carbon dioxide and water, releasing energy.
Equation:
Every C-H and C-C bond in the starting material is converted to a C-O bond in the product.
Incomplete Combustion
In the absence of sufficient oxygen, incomplete combustion occurs, forming carbon monoxide (CO) and water.
General Equation:
For methane:
Oxidation of saturated hydrocarbons is the basis for their use as energy sources for heat.
Summary Table
Topic | Key Reagents/Conditions | Main Products |
|---|---|---|
Oxidation (Baeyer's Test) | KMnO4 (alkaline) | Diols, brown MnO2 |
Oxidative Cleavage | Hot KMnO4, Ozone/Zn/HOAc | Carboxylates, aldehydes, ketones, CO2 |
Reduction | Pd/C, Lindlar's catalyst, Na/NH3 | Alkanes, cis-alkenes, trans-alkenes |
Acetylide Ion Formation | NaNH2, LDA, tBuLi | Acetylide ions |
Combustion | O2 (excess or limited) | CO2, H2O, CO |
Knowledge Check Examples
Which reaction conditions best convert 3-hexyne to cis-3-hexene? Answer: Lindlar's catalyst and H2
Classify the following transformation as oxidation or reduction: Alkene to alkane: Reduction Aldehyde to alcohol: Reduction
References
Carey, F.A. (2008) Organic Chemistry 7th ed. McGraw Hill
McMurry, J. (2008) Organic Chemistry 7th ed. Thomson Brooks Cole
Bruice, P.Y. (2017) Organic Chemistry 8th ed. Prentice Hall International
Brown W.H., Poon, T. (2016) Introduction to Organic Chemistry 6th ed. Wiley