Skip to main content
Ch. 5 - Normal Probability Distributions
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 5, Problem 5.4.29

Finding Probabilities for Sampling Distributions In Exercises 29–32, find the indicated probability and interpret the results.


Dow Jones Industrial Average From 1975 through 2020, the mean annual gain of the Dow Jones Industrial Average was 652. A random sample of 32 years is selected from this population. What is the probability that the mean gain for the sample was between 400 and 700? Assume sigma=1540

Verified step by step guidance
1
Step 1: Identify the key parameters of the problem. The population mean (μ) is 652, the population standard deviation (σ) is 1540, and the sample size (n) is 32. We are tasked with finding the probability that the sample mean (x̄) is between 400 and 700.
Step 2: Calculate the standard error of the mean (SE). The formula for the standard error is SE = σ / √n. Substitute the given values for σ and n into the formula to compute SE.
Step 3: Convert the sample mean values (400 and 700) into z-scores using the formula z = (x̄ - μ) / SE. Compute the z-scores for both 400 and 700 by substituting the respective values of x̄, μ, and SE.
Step 4: Use the standard normal distribution table (or a statistical software) to find the probabilities corresponding to the z-scores calculated in Step 3. These probabilities represent the cumulative probabilities up to the z-scores.
Step 5: Subtract the smaller cumulative probability (corresponding to the z-score for 400) from the larger cumulative probability (corresponding to the z-score for 700). This difference gives the probability that the sample mean is between 400 and 700.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
4m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Sampling Distribution

A sampling distribution is the probability distribution of a statistic obtained by selecting random samples from a population. It describes how the sample mean varies from sample to sample. The Central Limit Theorem states that, for a sufficiently large sample size, the sampling distribution of the sample mean will be approximately normally distributed, regardless of the population's distribution.
Recommended video:
05:11
Sampling Distribution of Sample Proportion

Standard Error

The standard error (SE) measures the dispersion of the sample means around the population mean. It is calculated as the population standard deviation divided by the square root of the sample size (SE = sigma / √n). A smaller standard error indicates that the sample mean is likely to be closer to the population mean, which is crucial for determining probabilities in sampling distributions.
Recommended video:
Guided course
08:45
Calculating Standard Deviation

Z-Score

A Z-score represents the number of standard deviations a data point is from the mean of a distribution. In the context of sampling distributions, it is used to calculate the probability of a sample mean falling within a certain range. The Z-score is calculated using the formula Z = (X - μ) / SE, where X is the sample mean, μ is the population mean, and SE is the standard error.
Recommended video:
Guided course
06:31
Z-Scores From Given Probability - TI-84 (CE) Calculator
Related Practice
Textbook Question

Graphical Analysis In Exercises 11–16, determine whether the graph could represent a variable with a normal distribution. Explain your reasoning. If the graph appears to represent a normal distribution, estimate the mean and standard deviation.

75
views
Textbook Question

Testing a Drug A drug manufacturer claims that a drug cures a rare skin disease 75% of the time. The claim is checked by testing the drug on 100 patients. If at least 70 patients are cured, then this claim will be accepted. Use this information in Exercises 31 and 32.


Find the probability that the claim will be accepted, assuming that the actual probability that the drug cures the skin disease is 65%.

118
views
Textbook Question

In Exercises 21–24, a control chart is shown. Each chart has horizontal lines drawn at the mean mu, at mu ±2sigma, and at mu±3sigma. Determine whether the process shown is in control or out of control. Explain.


A gear has been designed to have a diameter of 3 inches. The standard deviation of the process is 0.2 inch.


100
views
Textbook Question

"Getting Physical The figure shows the results of a survey of U.S. adults ages 18 to 29 who were asked whether they participated in a sport. In the survey, 48% of the men and 23% of the women said they participate in sports. The most common sports are shown below. Use this information in Exercises 29 and 30.


You randomly select 300 U.S. women ages 18 to 29 and ask them whether they participate in at least one sport. Of the 72 who say yes, 50% say they participate in volleyball. How likely is this result? Do you think this sample is a good one? Explain your reasoning."

44
views
Textbook Question

In Exercises 1–4, the sample size n, probability of success p, and probability of failure q are given for a binomial experiment. Determine whether you can use a normal distribution to approximate the distribution of x.

n=18, p=0.90, q=0.10

105
views
Textbook Question

Paint Cans A machine is set to fill paint cans with a mean of 128 ounces and a standard deviation of 0.2 ounce. A random sample of 40 cans has a mean of 127.9 ounces. The machine needs to be reset when the mean of a random sample is unusual. Does the machine need to be reset? Explain.

71
views