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Ch. 7 - Estimating Parameters and Determining Sample Sizes
Triola - Elementary Statistics 14th Edition
Triola14th EditionElementary StatisticsISBN: 9780137366446Not the one you use?Change textbook
Chapter 7, Problem 7.1.40

One-Sided Confidence Interval A one-sided claim about a population proportion is a claim that the proportion is less than (or greater than) some specific value. Such a claim can be formally addressed using a one-sided confidence interval for p, which can be expressed as p<p+E or p>p-E, where the margin of error E is modified by replacing za/2 with za. (Instead of dividing between two tails of the standard normal distribution, put all of it in one tail.) The Chapter Problem refers to a Sallie Mae survey of 950 undergraduate students, and 53% of the survey subjects take online courses. Use that data to construct a one-sided 95% confidence interval that would be suitable for helping to determine whether the percentage of all undergraduates who take online courses is greater than 50%.

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Step 1: Identify the given values from the problem. The sample size (n) is 950, the sample proportion (p̂) is 0.53 (53%), and the confidence level is 95%. For a one-sided confidence interval, the z-value (zα) corresponding to a 95% confidence level is approximately 1.645 (since all of the significance level is in one tail).
Step 2: Calculate the standard error (SE) of the sample proportion using the formula: SE = sqrt((p̂ * (1 - p̂)) / n). Substitute the values of p̂ = 0.53 and n = 950 into the formula.
Step 3: Compute the margin of error (E) for the one-sided confidence interval using the formula: E = zα * SE. Use the z-value of 1.645 and the standard error calculated in Step 2.
Step 4: Construct the one-sided confidence interval. Since the problem asks whether the percentage of all undergraduates who take online courses is greater than 50%, the one-sided confidence interval will be expressed as p > p̂ - E. Substitute the values of p̂ and E into this inequality.
Step 5: Interpret the result. The one-sided confidence interval provides a range of values for the population proportion p. If the lower bound of the interval is greater than 0.50, it supports the claim that the percentage of all undergraduates who take online courses is greater than 50%.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

One-Sided Confidence Interval

A one-sided confidence interval estimates a population parameter, such as a proportion, with a focus on one direction (either greater than or less than a specific value). Unlike two-sided intervals, which consider both tails of the distribution, one-sided intervals allocate the entire confidence level to one tail, allowing for a more precise assessment of claims about the population. This is particularly useful when testing hypotheses that predict a specific direction of effect.
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Margin of Error

The margin of error quantifies the uncertainty associated with a sample estimate of a population parameter. It reflects the range within which the true population parameter is expected to lie, given a certain confidence level. In the context of one-sided confidence intervals, the margin of error is adjusted to account for the directional nature of the hypothesis, impacting how we interpret the results and make decisions based on the data.
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Population Proportion

The population proportion is the fraction of a population that possesses a certain characteristic, often denoted as 'p'. In the context of surveys, it represents the percentage of respondents who affirmatively answer a question. Understanding the population proportion is crucial for constructing confidence intervals, as it serves as the basis for estimating how representative the sample data is of the larger population, influencing the conclusions drawn from statistical analyses.
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Related Practice
Textbook Question

Atkins Weight Loss Program In a test of weight loss programs, 40 adults used the Atkins weight loss program. After 12 months, their mean weight loss was found to be 2.1 lb, with a standard deviation of 4.8 lb. Construct a 90% confidence interval estimate of the standard deviation of the weight loss for all such subjects. Does the confidence interval give us information about the effectiveness of the diet?

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Textbook Question

Mean Assume that we want to use the sample data given in Exercise 1 with the bootstrap method to estimate the population mean. The mean of the values in Exercise 1 is 54.3 seconds, and the mean of all of the tobacco times in Data Set 20 “Alcohol and Tobacco in Movies” from Appendix B is 57.4 seconds. If we use 1000 bootstrap samples and find the corresponding 1000 means, do we expect that those 1000 means will target 54.3 seconds or 57.4 seconds? What does that result suggest about the bootstrap method in this case?

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Textbook Question

Female Motorcycle Owners Here is a 95% confidence interval estimate of the percentage of motorcycle owners who are female: 17.5%<p<20.6% (based on data from the Motorcycle Industry Council). What is the best point estimate of the percentage of motorcycle owners who are women?

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Textbook Question

Mint Specs Listed below are weights (grams) from a simple random sample of pennies produced after 1983 (from Data Set 40 “Coin Weights” in Appendix B). Construct a 95% confidence interval estimate of for the population of such pennies. What does the confidence interval suggest about the U.S. Mint specifications that now require a standard deviation of 0.0230 g for weights of pennies?

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Textbook Question

use the given information to find the number of degrees of freedom, the critical values X2L and X2R, and the confidence interval estimate of σ. It is reasonable to assume that a simple random sample has been selected from a population with a normal distribution:


Heights of Men 99% confidence; n=153, s=7.10 cm.

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Textbook Question

Critical Thinking. In Exercises 17–28, use the data and confidence level to construct a confidence interval estimate of p, then address the given question.


Measured Results vs. Reported Results The same study cited in the preceding exercise produced these results after six months for the 198 patients given sustained care: 25.8% were no longer smoking, and these results were biochemically confirmed, but 40.9% of these patients reported that they were no longer smoking. Construct the two 95% confidence intervals. Compare the results. What do you conclude?

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