find-the-value-of-hehprimelefteright-where-hx3x13xhleftxrightleft3xrightfrac13x-

Question

Find the value of $h^{'} (e)$ where $h (x) = {(3 x)}^{\frac{1}{3 x}}$ , and $e$ is the base of the natural logarithm.

Accepted Answer

$h^{'} (e) = - \frac{{(3 e)}^{\frac{1}{3 e}} \ln 3}{3 e^{2}}$

Answer

$h^{'} (e) = - \frac{{(3 e)}^{\frac{1}{3 e}} \ln 3}{3 e^{2}}$

Answer

$h^{'} (e) = - \frac{{(3 e)}^{\frac{1}{3 e}} \ln 3}{3 e^{2}}$

Answer

$h^{'} (e) = - \frac{{(3 e)}^{\frac{1}{3 e}} \ln 3}{3 e^{2}}$

Find the value of h′(e)h^{\prime}\left(e\right) where h(x)=(3x)13xh\left(x\right)=\left(3x\right)^{\frac{1}{3x}}, and ee is the base of the natural logarithm.