Calculus
Find a possible function h(x)h\(\left\)(x\(\right\)) and a number cc such that the following limit represents the slope of the curve y=h(x)y=h\(\left\)(x\(\right\)) at (c,h(c))(c,h(c)). Then, evaluate the limit:
limx→−14x2−2x−6x+1{\(\displaystyle\]\lim\)_{x\(\to\)-1}}\(\frac{4x^2-2x-6}{x+1}\)
Determine the derivative of the function g(t)=5t2+2tg(t)=5t^2+2t using limits.
The following formulas for f−′(a)f_{-}^{\(\prime\)}\(\left\)(a\(\right\)) and f+′(a)f_{+}^{\(\prime\)}\(\left\)(a\(\right\)) represent the left- and right-sided derivatives of a function at a point aa, respectively:
f−′(a)=limh→0−f(a+h)−f(a)hf_{-}^{\(\prime\)}\(\left\)(a\(\right\))={\(\displaystyle\]\lim\)_{h\(\to\)0^{-}}{\(\frac{f(a+h)-f(a)}{h}\)}}, f+′(a)=limh→0+f(a+h)−f(a)hf_{+}^{\(\prime\)}\(\left\)(a\(\right\))={\(\displaystyle\]\lim\)_{h\(\to\)0^{+}}{\(\frac{f(a+h)-f(a)}{h}\)}}
Consider f(x)={6−x2 if x≤23x−4 if x>2f\(\left\)(x\(\right\))=\(\begin{cases}\)6-x^2~~~\(\text{if}\)~x\(\leq{2}\)\\ 3x-4~~~\(\text{if}\)~x\(\gt{2}\]\end{cases}\). Find f−′(a)f_{-}^{\(\prime\)}\(\left\)(a\(\right\)) and f+′(a)f_{+}^{\(\prime\)}\(\left\)(a\(\right\)) at a=2a=2.