The first-order rate constant for the decomposition of
N2O5, 2 N2...

Question

The first-order rate constant for the decomposition of
N2O5, 2 N2O51g2¡4 NO21g2 + O21g2, a t 70 C i s
6.82 * 10-3 s-1. Suppose we start with 0.0250 mol of
N2O51g2 in a volume of 2.0 L.
(c) What is the half-life of N2O5 at 70 C ?

Accepted Answer

Hello everyone. Today, we have the following problem. The thermal d hydrogenation of propane is a first order process and has a rate constant of 4.86 times 10 to the negative second seconds to the negative one at 873. Kelvin, Calculate the Half Life of Propane at 873 Kelvin. So the first thing you wanna do is you want to write our formula for half life And it's going to be the natural log of two divided by a constant K. And so we have our constant K, our rate constant given us in the question stem. So we simply plug it in, we have our natural log two divided by our constant, which was 4.86 times 10 to the negative two seconds to the negative one. And this is going to give us a half life of 14.3 seconds. And with that, we have answered the question overall, I hope this helped. And until next time.

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