BackStep-by-Step Genetics Study Guide: DNA Structure, Replication, Organization, Transcription, and Translation
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Q1. To serve as genetic material, a molecule must be able to do what five things?
Background
Topic: Properties of Genetic Material
This question tests your understanding of the essential characteristics that a molecule must possess to function as genetic material in living organisms.
Key Terms:
Genetic material
Replication
Storage of information
Expression of information
Variation
Transmission
Step-by-Step Guidance
Recall the main functions that genetic material must fulfill in order to be considered the basis of heredity.
Think about how genetic material must be able to store information for the development and functioning of an organism.
Consider how genetic material must be able to replicate accurately so that information can be passed to the next generation.
Reflect on how genetic material must be able to express its information to direct cellular processes.
Remember that genetic material must be able to undergo variation to allow for evolution and adaptation.
Try to list these five essential properties before checking the answer.
Try solving on your own before revealing the answer!
Final Answer:
Replication: Must be able to replicate accurately.
Storage: Must store information.
Expression: Must express information.
Variation: Must be able to undergo variation/mutation.
Transmission: Must be able to transmit information to the next generation.
These five properties are essential for any molecule to serve as genetic material.
Q2. Write the central dogma of molecular genetics and the names of the two processes.
Background
Topic: Central Dogma of Molecular Biology
This question is about the flow of genetic information in cells and the processes involved.
Key Terms and Formulas:
Central dogma
Transcription
Translation
Step-by-Step Guidance
Recall the sequence in which genetic information is transferred from DNA to protein.
Identify the process that converts DNA into RNA.
Identify the process that converts RNA into protein.
Write out the central dogma in the correct order and name the two processes.
Try solving on your own before revealing the answer!
Final Answer:
The central dogma is:
The two processes are transcription and translation.
Q3. What did the experiment of Griffith (1927) demonstrate?
Background
Topic: Discovery of Transformation Principle
This question tests your knowledge of classic experiments that led to the identification of DNA as genetic material.
Key Terms:
Transformation
Virulent and non-virulent strains
Pneumococcus
Step-by-Step Guidance
Recall the two types of bacterial strains used in Griffith's experiment (smooth and rough).
Think about what happened when heat-killed virulent bacteria were mixed with live non-virulent bacteria.
Consider the outcome in mice and what it suggested about the transfer of genetic material.
Try to summarize what principle was demonstrated by this experiment.
Try solving on your own before revealing the answer!
Final Answer:
Griffith's experiment demonstrated the phenomenon of transformation, showing that genetic material from dead virulent bacteria could be transferred to live non-virulent bacteria, making them virulent.
Q4. What did the experiment of Avery, MacLeod, and McCarty (1944) demonstrate?
Background
Topic: Identification of DNA as Genetic Material
This question is about the experiment that provided evidence that DNA is the substance responsible for heredity.
Key Terms:
Transformation
DNA, RNA, protein
Enzymatic degradation
Step-by-Step Guidance
Recall how the experiment built on Griffith's findings.
Think about how the researchers used enzymes to selectively destroy DNA, RNA, or protein.
Consider which treatment prevented transformation and what this indicated about the genetic material.
Try to state the main conclusion of the experiment.
Try solving on your own before revealing the answer!
Final Answer:
Avery, MacLeod, and McCarty demonstrated that DNA is the transforming principle, providing strong evidence that DNA is the genetic material responsible for heredity.
Q5. Explain how the experiment of Hershey and Chase (1952) was done.
Background
Topic: DNA as Genetic Material in Viruses
This question tests your understanding of the experiment that confirmed DNA as the genetic material using bacteriophages.
Key Terms:
Bacteriophage
Radioactive labeling
Phosphorus-32 () and Sulfur-35 ()
DNA and protein
Step-by-Step Guidance
Recall that Hershey and Chase used bacteriophages to infect bacteria.
Think about how they labeled DNA with and protein with .
Consider what happened after infection and which component entered the bacterial cells.
Try to describe the steps of the experiment and what was concluded.
Try solving on your own before revealing the answer!
Final Answer:
Hershey and Chase used radioactive isotopes to label DNA and protein in bacteriophages. After infection, only the DNA (labeled with ) entered the bacterial cells, demonstrating that DNA is the genetic material.
Q6. List the four different types of genomes that viruses can have.
Background
Topic: Viral Genomes
This question is about the diversity of genetic material found in viruses.
Key Terms:
DNA viruses
RNA viruses
Single-stranded
Double-stranded
Step-by-Step Guidance
Recall that viruses can have either DNA or RNA as their genetic material.
Think about the strandedness (single or double) of these genomes.
Try to list all four possible types.
Try solving on your own before revealing the answer!
Final Answer:
Double-stranded DNA (dsDNA)
Single-stranded DNA (ssDNA)
Double-stranded RNA (dsRNA)
Single-stranded RNA (ssRNA)
Q7. What is the function of the enzyme reverse transcriptase?
Background
Topic: Enzymes in Viral Replication
This question is about the enzyme that allows certain viruses to copy their RNA into DNA.
Key Terms:
Reverse transcriptase
Retrovirus
RNA to DNA
Step-by-Step Guidance
Recall which type of virus uses reverse transcriptase.
Think about the direction of information flow catalyzed by this enzyme.
Try to state the function of reverse transcriptase.
Try solving on your own before revealing the answer!
Final Answer:
Reverse transcriptase synthesizes DNA from an RNA template, allowing retroviruses to integrate their genetic material into the host genome.
Q8. List the names of the three parts of a nucleotide.
Background
Topic: Nucleotide Structure
This question tests your knowledge of the basic building blocks of nucleic acids.
Key Terms:
Nucleotide
Phosphate group
Pentose sugar
Nitrogenous base
Step-by-Step Guidance
Recall the three components that make up a nucleotide.
Try to name each part and describe its role in the nucleotide structure.
Try solving on your own before revealing the answer!
Final Answer:
Nitrogenous base
Pentose sugar (ribose or deoxyribose)
Phosphate group
Q9. List the names of the two bases which are classified as purines. Be able to recognize the structure of each of them.
Background
Topic: Nitrogenous Bases
This question is about the classification of bases in nucleic acids and their structural features.
Key Terms:
Purines
Adenine
Guanine
Double-ring structure
Step-by-Step Guidance
Recall which bases are purines in DNA and RNA.
Think about the structural features that distinguish purines from pyrimidines.
Try to name the two purines and describe their structure.
Try solving on your own before revealing the answer!
Final Answer:
Adenine (A)
Guanine (G)
Both have a double-ring structure characteristic of purines.
Q10. List the names of the three bases which are classified as pyrimidines. Be able to recognize the structure of each of them.
Background
Topic: Nitrogenous Bases
This question is about the classification of pyrimidine bases and their structural features.
Key Terms:
Pyrimidines
Cytosine
Thymine
Uracil
Single-ring structure
Step-by-Step Guidance
Recall which bases are pyrimidines in DNA and RNA.
Think about the structural features that distinguish pyrimidines from purines.
Try to name the three pyrimidines and describe their structure.
Try solving on your own before revealing the answer!
Final Answer:
Cytosine (C)
Thymine (T) – found in DNA
Uracil (U) – found in RNA
All have a single-ring structure characteristic of pyrimidines.
Q11. Be able to recognize the structure of ribose sugar and deoxyribose sugar. Number the carbon atoms in each sugar.
Background
Topic: Sugar Components of Nucleic Acids
This question is about the structural differences between ribose and deoxyribose sugars in nucleic acids.
Key Terms:
Ribose
Deoxyribose
Pentose sugar
Carbon numbering
Step-by-Step Guidance
Recall the chemical structure of ribose and deoxyribose.
Identify the difference at the 2' carbon position between the two sugars.
Practice numbering the carbons from 1' to 5' in the sugar ring.
Try to draw or visualize the structure and label the carbons.
Try solving on your own before revealing the answer!
Final Answer:
Ribose has a hydroxyl group (-OH) at the 2' carbon, while deoxyribose has a hydrogen (H) at the 2' carbon. Both sugars have carbons numbered 1' through 5'.
Q12. Differentiate between a nucleoside and a nucleotide.
Background
Topic: Nucleic Acid Components
This question is about the difference between nucleosides and nucleotides.
Key Terms:
Nucleoside
Nucleotide
Phosphate group
Step-by-Step Guidance
Recall the components of a nucleoside.
Recall the components of a nucleotide.
Identify the key difference between the two.
Try solving on your own before revealing the answer!
Final Answer:
A nucleoside consists of a nitrogenous base and a sugar. A nucleotide consists of a nitrogenous base, a sugar, and a phosphate group.
Q13. Identify the structure of a phosphodiester bond.
Background
Topic: Nucleic Acid Backbone
This question is about the chemical bond that links nucleotides together in DNA and RNA.
Key Terms:
Phosphodiester bond
3' and 5' carbon
Backbone
Step-by-Step Guidance
Recall how nucleotides are linked together in a nucleic acid strand.
Identify which carbons are involved in the bond.
Try to describe or draw the structure of the phosphodiester bond.
Try solving on your own before revealing the answer!
Final Answer:
A phosphodiester bond links the 5' phosphate group of one nucleotide to the 3' hydroxyl group of another nucleotide, forming the backbone of DNA and RNA.
Q14. List the three Chargaff rules.
Background
Topic: Base Composition of DNA
This question is about the empirical rules discovered by Chargaff regarding the ratios of bases in DNA.
Key Terms:
Chargaff's rules
Base pairing
Purines and pyrimidines
Step-by-Step Guidance
Recall the relationships between adenine, thymine, guanine, and cytosine in DNA.
Think about the ratios of purines to pyrimidines.
Try to list the three main rules.
Try solving on your own before revealing the answer!
Final Answer:
The amount of adenine (A) equals the amount of thymine (T):
The amount of guanine (G) equals the amount of cytosine (C):
The total amount of purines (A + G) equals the total amount of pyrimidines (T + C):
Q15. List the key structural features of double-stranded DNA.
Background
Topic: DNA Structure
This question is about the physical and chemical features of the DNA double helix.
Key Terms:
Double helix
Antiparallel strands
Base pairing
Major and minor grooves
Step-by-Step Guidance
Recall the overall shape of double-stranded DNA.
Think about the orientation of the two strands.
Consider the types of bonds holding the strands together.
Try to list the key structural features.
Try solving on your own before revealing the answer!
Final Answer:
Double helix structure
Antiparallel strands (5' to 3' and 3' to 5')
Complementary base pairing (A-T, G-C)
Major and minor grooves
Phosphodiester backbone
Q16. How are complementary base pairs in dsDNA bonded? How many bonds are found with each pair of bases?
Background
Topic: Base Pairing in DNA
This question is about the chemical bonds that hold the two strands of DNA together.
Key Terms:
Hydrogen bonds
A-T pair
G-C pair
Step-by-Step Guidance
Recall the type of bond that forms between complementary bases.
Think about the number of bonds between A-T and G-C pairs.
Try to state the bonding details for each pair.
Try solving on your own before revealing the answer!
Final Answer:
Complementary base pairs are bonded by hydrogen bonds: A-T pairs have 2 hydrogen bonds, G-C pairs have 3 hydrogen bonds.
Q17. List three differences in the structure of RNA compared to DNA.
Background
Topic: DNA vs. RNA Structure
This question is about the structural differences between DNA and RNA molecules.
Key Terms:
Ribose vs. deoxyribose
Uracil vs. thymine
Single-stranded vs. double-stranded
Step-by-Step Guidance
Recall the sugar component in RNA and DNA.
Think about the nitrogenous bases present in each molecule.
Consider the strandedness of RNA and DNA.
Try to list three structural differences.
Try solving on your own before revealing the answer!
Final Answer:
RNA contains ribose sugar; DNA contains deoxyribose.
RNA uses uracil instead of thymine.
RNA is usually single-stranded; DNA is double-stranded.
Q18. List the names of the three main classes of RNA molecules and their basic functions.
Background
Topic: Types of RNA
This question is about the major classes of RNA and their roles in the cell.
Key Terms:
mRNA
tRNA
rRNA
Step-by-Step Guidance
Recall the three main types of RNA found in cells.
Think about the function of each type.
Try to list the names and functions.
Try solving on your own before revealing the answer!
Final Answer:
Messenger RNA (mRNA): carries genetic information from DNA to the ribosome.
Transfer RNA (tRNA): brings amino acids to the ribosome during translation.
Ribosomal RNA (rRNA): forms the core of the ribosome and catalyzes protein synthesis.