A rocket-powered hockey puck moves on a horizontal frictionless table. Figure EX4.7 shows graphs of v_x and v_y the x- and y-components of the puck's velocity. The puck starts at the origin. What is the magnitude of the puck's acceleration at t = 5s?

A particle's trajectory is described by $x=(\frac{1}{2}{t}^3-2t^2)\text{m}\text{and}y=(\frac{1}{2}{t}^2-2t)\text{m},$ where $t$ is in $s$. What are the particle's position and speed at $t=0\text{ s}$ and $t=4\text{ s}$?

A particle's trajectory is described by $x = \(\left\)(\(\frac{1}{2}\) t^3 - 2t^2\(\right\)) \, \(\text{m}\) \(\quad\) \(\text{and}\) \(\quad\) y = \(\left\)(\(\frac{1}{2}\) t^2 - 2t\(\right\)) \, \(\text{m}\),$ where $t$ is in $s$. What is the particle's direction of motion, measured as an angle from the $x$-axis, at $t=0\(\text{ s}\)$ and $t=4\(\text{ s}\)$?

A rocket-powered hockey puck moves on a horizontal frictionless table. FIGURE EX4.6 shows graphs of v_x and v_y, the x- and y-components of the puck's velocity. The puck starts at the origin. How far from the origin is the puck at t = 5s?

A particle moving in the xy-plane has velocity v = (2ti + (3-t²)j) m/s, where t is in s. What is the particle's acceleration vector at t = 4s?

Is this particle curving upward, curving downward, or moving in a straight line?

A rocket-powered hockey puck moves on a horizontal frictionless table. FIGURE EX4.6 shows graphs of v_x and v_y, the x- and y-components of the puck's velocity. The puck starts at the origin. In which direction is the puck moving at t = 2s? Give your answer as an angle from the x-axis.