A 6.00-cm-diameter sphere with a mass of 89.3 g is neutrally buoyant in a liquid. Identify the liquid.

검증된 단계별 안내

Determine the volume of the sphere using the formula for the volume of a sphere:

V = \frac{4}{3} π r^{3}

, where

r

is the radius of the sphere. Convert the diameter (6.00 cm) to radius (3.00 cm) and substitute it into the formula.

Calculate the density of the sphere using the formula

ρ = \frac{m}{V}

, where

m

is the mass of the sphere (89.3 g) and

V

is the volume calculated in the previous step. Ensure the units are consistent (e.g., convert mass to kilograms and volume to cubic meters if necessary).

Since the sphere is neutrally buoyant, its density is equal to the density of the liquid. This is because the buoyant force equals the gravitational force when an object is neutrally buoyant, implying that the densities are equal.

Identify the liquid by comparing the calculated density of the sphere (which is the same as the liquid's density) to known densities of liquids. Use a reference table of liquid densities to find the match.

Verify the result by ensuring the calculated density aligns with the physical properties of the identified liquid and that the assumptions made (e.g., neutral buoyancy) are valid for the problem.

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이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Buoyancy

Buoyancy is the upward force exerted by a fluid on an object submerged in it. This force counteracts the weight of the object, allowing it to float or remain suspended. An object is neutrally buoyant when the buoyant force equals its weight, resulting in no net force acting on it.

Density

Density is defined as mass per unit volume and is a key factor in determining whether an object will float or sink in a fluid. For an object to be neutrally buoyant, its density must equal the density of the fluid it is in. The formula for density is ρ = m/V, where ρ is density, m is mass, and V is volume.

Volume of a Sphere

The volume of a sphere can be calculated using the formula V = (4/3)πr³, where r is the radius of the sphere. This volume is essential for determining the density of the sphere when combined with its mass. In this case, knowing the diameter allows us to find the radius and subsequently the volume, which is necessary for identifying the liquid in which the sphere is neutrally buoyant.