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Ch. 5 - Normal Probability Distributions
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 5, Problem 5.5.20a

Approximating Binomial Probabilities In Exercises 19–26, determine whether you can use a normal distribution to approximate the binomial distribution. If you can, use the normal distribution to approximate the indicated probabilities and sketch their graphs. If you cannot, explain why and use a binomial distribution to find the indicated probabilities. Identify any unusual events. Explain.


Social Media A survey of Americans found that 55% would be disappointed if Facebook disappeared. You randomly select 500 Americans and ask them whether they would be disappointed if Facebook disappeared. Find the probability that the number who say yes is (a) less than 250

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Step 1: Verify if the normal approximation to the binomial distribution can be used. The conditions are: (1) The sample size (n) is large, and (2) both np and n(1-p) are greater than or equal to 5. Here, n = 500 and p = 0.55. Calculate np = 500 * 0.55 and n(1-p) = 500 * (1 - 0.55). Check if both values meet the condition.
Step 2: If the conditions are satisfied, approximate the binomial distribution using a normal distribution. The mean (μ) and standard deviation (σ) of the binomial distribution are given by μ = np and σ = √(np(1-p)). Calculate these values.
Step 3: Apply the continuity correction for the normal approximation. Since the problem asks for the probability that the number is less than 250, adjust the value to 249.5 to account for the discrete-to-continuous transition.
Step 4: Standardize the value using the z-score formula: z = (x - μ) / σ, where x is the adjusted value (249.5), μ is the mean, and σ is the standard deviation. Compute the z-score.
Step 5: Use the standard normal distribution table (or a calculator) to find the cumulative probability corresponding to the calculated z-score. This will give the probability that the number of Americans who say yes is less than 250. Sketch the normal curve, marking the mean and the area corresponding to the probability.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Binomial Distribution

A binomial distribution models the number of successes in a fixed number of independent Bernoulli trials, each with the same probability of success. It is characterized by two parameters: the number of trials (n) and the probability of success (p). In this context, the survey of Americans represents a binomial scenario where each individual either expresses disappointment (success) or not (failure).
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Normal Approximation to the Binomial

The normal approximation to the binomial distribution is applicable when the number of trials is large, and both np and n(1-p) are greater than 5. This allows us to use the normal distribution to estimate probabilities for binomial outcomes, simplifying calculations. In this case, with n=500 and p=0.55, we can check these conditions to determine if the normal approximation is valid.
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Unusual Events

An unusual event in statistics is typically defined as an outcome that has a low probability of occurring, often less than 5%. In the context of the binomial distribution, identifying unusual events helps in understanding the likelihood of certain outcomes, such as finding the probability of fewer than 250 people expressing disappointment. This concept is crucial for interpreting results and making informed decisions based on statistical data.
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Related Practice
Textbook Question

Red Blood Cell Count Use the normal distribution in Exercise 16.


a. What percent of the adult males have a red blood cell count less than 6 million cells per microliter?

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Textbook Question

Finding Specified Data Values In Exercises 31–38, answer the questions about the specified normal distribution.


Advanced Dental Admission Test The Advanced Dental Admission Test (ADAT) is designed so that the scores fit a normal distribution, as shown in the figure. (Source: American Dental Association)



b. Between what two values does the middle 50% of the ADAT scores lie?

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Textbook Question

Finding Probabilities for Normal Distributions In Exercises 7–12, find the indicated probabilities. If convenient, use technology to find the probabilities.

         

Health Club Schedule The amounts of time per workout an athlete uses a stairclimber are normally distributed, with a mean of 20 minutes and a standard deviation of 5 minutes. Find the probability that a randomly selected athlete uses a stairclimber for (a) less than 17 minutes.

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Textbook Question

SAT Total Scores Use the normal distribution in Exercise 13.

b. Out of 1000 randomly selected SAT total scores, about how many would you expect to be greater than 1100?

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Textbook Question

Uniform Distribution A uniform distribution is a continuous probability distribution for a random variable x between two values a and b (a<b), where (a ≤ x ≤ b) and all of the values of x are equally likely to occur. The graph of a uniform distribution is shown below.

The probability density function of a uniform distribution is


on the interval from (x=a) to (x=b). For any value of x less than a or greater than b, y=0 . In Exercises 59 and 60, use this information.


For two values c and d, where a ≤ c < d ≤ b, the probability that x lies between c and d is equal to the area under the curve between c and d, as shown below.



So, the area of the red region equals the probability that x lies between c and d. For a uniform distribution from (a=1) to (b=25) , find the probability that


a. x lies between 2 and 8.

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Textbook Question

Approximating Binomial Probabilities In Exercises 19–26, determine whether you can use a normal distribution to approximate the binomial distribution. If you can, use the normal distribution to approximate the indicated probabilities and sketch their graphs. If you cannot, explain why and use a binomial distribution to find the indicated probabilities. Identify any unusual events. Explain.


Athletes on Social Issues In a survey of college athletes, 84% said they are willing to speak up and be more active in social issues. You randomly select 25 college athletes. Find the probability that the number who are willing to speak up and be more active in social issues is (a) at least 24

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