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Ch. 5 - Normal Probability Distributions
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 5, Problem 5.1.48

Finding Probability In Exercises 47–56, find the indicated probability using the standard normal distribution. If convenient, use technology to find the probability.


P(z < - 1.11)

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Step 1: Understand the problem. The goal is to find the probability that the standard normal variable Z is less than -1.11, denoted as P(z < -1.11). The standard normal distribution has a mean of 0 and a standard deviation of 1.
Step 2: Recall that the standard normal distribution is symmetric, and probabilities can be found using a Z-table or technology (e.g., statistical software or a calculator). The Z-table provides cumulative probabilities for Z-values.
Step 3: Locate the Z-value of -1.11 in the Z-table. The table will give the cumulative probability for Z-values less than -1.11. If using technology, input the Z-value into the software or calculator to find the cumulative probability.
Step 4: Interpret the cumulative probability. The value obtained represents the area under the standard normal curve to the left of Z = -1.11.
Step 5: If using technology, verify the result by ensuring the input matches the problem (P(z < -1.11)). If using the Z-table, double-check the row and column corresponding to -1.11 to ensure accuracy.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Standard Normal Distribution

The standard normal distribution is a special case of the normal distribution where the mean is 0 and the standard deviation is 1. It is represented by the variable Z, which allows for the calculation of probabilities and percentiles for any normal distribution by standardizing values. This transformation is crucial for comparing different datasets and finding probabilities associated with specific Z-scores.
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Z-Score

A Z-score indicates how many standard deviations an element is from the mean of a distribution. It is calculated by subtracting the mean from the value and then dividing by the standard deviation. In the context of the standard normal distribution, a Z-score of -1.11 means the value is 1.11 standard deviations below the mean, which is essential for determining the corresponding probability.
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Cumulative Probability

Cumulative probability refers to the probability that a random variable takes on a value less than or equal to a specific value. In the context of the standard normal distribution, P(z < -1.11) represents the cumulative probability of Z being less than -1.11. This probability can be found using Z-tables or statistical software, providing insights into the likelihood of observing values in a given range.
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Related Practice
Textbook Question

Finding Area

In Exercises 23–36, find the indicated area under the standard normal curve. If convenient, use technology to find the area.


To the left of z=1.365

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Textbook Question

Bags of Baby Carrots The weights of bags of baby carrots are normally distributed, with a mean of 32 ounces and a standard deviation of 0.36 ounce. Bags in the upper 4.5% are too heavy and must be repackaged. What is the most a bag of baby carrots can weigh and not need to be repackaged?

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Textbook Question

Interpreting the Central Limit Theorem In Exercises 19–26, find the mean and standard deviation of the indicated sampling distribution of sample means. Then sketch a graph of the sampling distribution.


Renewable Energy The zloty is the official currency of Poland. During a recent period of two years, the day-ahead prices for renewable energy in Poland (in zlotys per mega-watt hour) have a mean of 158.51 and a standard deviation of 33.424. Random samples of size 100 are drawn from this population, and the mean of each sample is determined. (Adapted from Multidisciplinary Digital Publishing Institute)

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Textbook Question

Conservation About 74% of the residents in a town say that they are making an effort to conserve water or electricity. One hundred ten residents are randomly selected. What is the probability that the sample proportion making an effort to conserve water or electricity is greater than 80%? Interpret your result.

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Textbook Question

Computing Probabilities for Normal Distributions In Exercises 1–6, the random variable x is normally distributed with mean mu=174 and standard deviation sigma=20. Find the indicated probability.


P(x > 182)

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Textbook Question

True or False? In Exercises 5–8, determine whether the statement is true or false. If it is false, rewrite it as a true statement.


As the sample size increases, the standard deviation of the distribution of sample means increases.

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