Skip to main content
Ch. 8 - Hypothesis Testing with Two Samples
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 8, Problem 8.2.2

Explain how to perform a two-sample t-test for the difference between two population means.

Verified step by step guidance
1
Step 1: State the null hypothesis (H₀) and the alternative hypothesis (Hₐ). The null hypothesis typically assumes that the two population means are equal (H₀: μ₁ = μ₂), while the alternative hypothesis assumes they are not equal (Hₐ: μ₁ ≠ μ₂) or that one mean is greater/less than the other, depending on the context of the problem.
Step 2: Check the assumptions for the two-sample t-test. These include: (1) the samples are independent, (2) the populations are approximately normally distributed (or the sample sizes are large enough for the Central Limit Theorem to apply), and (3) the population variances are equal if using the pooled t-test (or unequal if using the Welch's t-test).
Step 3: Calculate the test statistic. For the pooled t-test, use the formula: t = (x1 - x2)(sp)2(1n1 + 1n2, where sp is the pooled standard deviation. For Welch's t-test, adjust the formula to account for unequal variances.
Step 4: Determine the degrees of freedom. For the pooled t-test, use df=n1 + n2 - 2. For Welch's t-test, use the Welch-Satterthwaite equation to approximate the degrees of freedom.
Step 5: Compare the calculated test statistic to the critical value from the t-distribution table (or use the p-value approach). If the test statistic falls in the rejection region or the p-value is less than the significance level (α), reject the null hypothesis. Otherwise, fail to reject the null hypothesis.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
6m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Two-Sample t-Test

A two-sample t-test is a statistical method used to determine if there is a significant difference between the means of two independent groups. It assumes that the samples are drawn from normally distributed populations with unknown but equal variances. This test helps in comparing the means to infer whether any observed difference is statistically significant.
Recommended video:
05:11
Sampling Distribution of Sample Proportion

Null Hypothesis and Alternative Hypothesis

In hypothesis testing, the null hypothesis (H0) states that there is no effect or difference between the groups, while the alternative hypothesis (H1) posits that there is a significant difference. For a two-sample t-test, the null hypothesis typically asserts that the means of the two populations are equal, and the test aims to provide evidence to either reject or fail to reject this hypothesis based on sample data.
Recommended video:
Guided course
06:21
Step 1: Write Hypotheses

P-Value and Significance Level

The p-value is a measure that helps determine the strength of the evidence against the null hypothesis. It represents the probability of observing the data, or something more extreme, if the null hypothesis is true. The significance level (commonly set at 0.05) is the threshold for deciding whether to reject the null hypothesis; if the p-value is less than this level, the result is considered statistically significant.
Recommended video:
Guided course
06:50
Step 3: Get P-Value
Related Practice
Textbook Question

Test the claim about the mean of the differences for a population of paired data at the level of significance α. Assume the samples are random and dependent, and the populations are normally distributed.

Claim: μd<0 , α=0.05 , Sample statistics: d̄ =1.5 , sd=3.2 , n=14

84
views
Textbook Question

In Exercises 11–14, test the claim about the difference between two population means and at the level of significance . Assume the samples are random and independent, and the populations are normally distributed.

Claim: μ1>μ2; α=0.10

Population statistics:σ1=40 and σ2=15

Sample Statistics: x̅1=500, n1=100, x̅2=495, n2=75

55
views
Textbook Question

Test the claim about the difference between two population means and at the level of significance α. Assume the samples are random and independent, and the populations are normally distributed.

Claim: μ1>μ2, α=0.01, Assume (σ1)^2≠(σ2)^2 

Sample statistics:

x̅1=52, s1=4.8, n1=32 and x̅2=50, s2=1.2, n2=40

68
views
Textbook Question

Parks and Mental Health In Exercises 13–18, use the figure, which shows the percentages from a survey of two hundred 18- to 24-year-olds in the United States who say that various park and recreation activities have a positive impact on their mental health. (Adapted from National Recreation and Park Association)



Socializing and Taking Classes At α=0.05, can you support the claim that the proportion of 18- to 24-year-olds who benefit mentally from socializing in parks is different from the proportion who benefit mentally from taking classes in parks?

48
views
Textbook Question

In Exercises 11–14, test the claim about the difference between two population means and at the level of significance . Assume the samples are random and independent, and the populations are normally distributed.

Claim: μ1=μ2; α=0.1

Population statistics:σ1=3.4 and σ2=1.5

Sample Statistics: x̅1=16, n1=29, x̅2=14, n2=28

51
views
Textbook Question

[APPLET] Tensile Strength

The tensile strength of a metal is a measure of its ability to resist tearing when it is pulled lengthwise. An experimental method of treatment produced steel bars with the tensile strengths (in newtons per square millimeter) listed below.

Experimental Method:

391 383 333 378 368 401 339 376 366 348

The conventional method produced steel bars with the tensile strengths (in newtons per square millimeter) listed below.

Conventional Method:

362 382 368 398 381 391 400410 396 411 385 385 395 371

At , α=0.01 can you support the claim that the experimental method of treatment makes a difference in the tensile strength of steel bars? Assume the population variances are equal.

48
views