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Ch. 8 - Hypothesis Testing with Two Samples
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 8, Problem 8.1.12

In Exercises 11–14, test the claim about the difference between two population means and at the level of significance . Assume the samples are random and independent, and the populations are normally distributed.
Claim: μ1>μ2; α=0.10
Population statistics:σ1=40 and σ2=15
Sample Statistics: x̅1=500, n1=100, x̅2=495, n2=75

Verified step by step guidance
1
Identify the null and alternative hypotheses based on the claim μ1 > μ2. The null hypothesis is \(H_0: \mu_1 \leq \mu_2\) and the alternative hypothesis is \(H_a: \mu_1 > \mu_2\).
Determine the significance level, which is given as \(\alpha = 0.10\). This will be used to find the critical value for the test.
Calculate the test statistic for the difference between two population means when population standard deviations are known. Use the formula: \[ Z = \frac{(\bar{x}_1 - \bar{x}_2) - (\mu_1 - \mu_2)}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}} \] Since under the null hypothesis \(\mu_1 - \mu_2 = 0\), simplify accordingly.
Find the critical value from the standard normal distribution corresponding to the right-tailed test at \(\alpha = 0.10\). This critical value will be used to compare with the calculated test statistic.
Compare the calculated test statistic to the critical value: if the test statistic is greater than the critical value, reject the null hypothesis; otherwise, do not reject the null hypothesis. This will determine if there is sufficient evidence to support the claim \(\mu_1 > \mu_2\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Hypothesis Testing for Two Population Means

This involves comparing two population means to determine if there is enough evidence to support a specific claim. The null hypothesis typically states no difference (μ1 = μ2), while the alternative reflects the claim (μ1 > μ2). The test uses sample data to decide whether to reject the null hypothesis at a given significance level.
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Difference in Means: Hypothesis Tests

Significance Level (α)

The significance level, α, is the threshold probability for rejecting the null hypothesis when it is true (Type I error). Here, α = 0.10 means there is a 10% risk of incorrectly rejecting the null. It sets the critical value or rejection region for the test statistic.
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Z-Test for Difference Between Means with Known Population Standard Deviations

When population standard deviations (σ1 and σ2) are known and samples are independent and normal, a Z-test is used. The test statistic measures how far the sample mean difference is from zero, scaled by the standard error. This helps determine if the observed difference is statistically significant.
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Related Practice
Textbook Question

Test the claim about the mean of the differences for a population of paired data at the level of significance α. Assume the samples are random and dependent, and the populations are normally distributed.

Claim: μd<0 , α=0.05 , Sample statistics: d̄ =1.5 , sd=3.2 , n=14

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Textbook Question

Test the claim about the difference between two population means and at the level of significance α. Assume the samples are random and independent, and the populations are normally distributed.

Claim: μ1>μ2, α=0.01, Assume (σ1)^2≠(σ2)^2 

Sample statistics:

x̅1=52, s1=4.8, n1=32 and x̅2=50, s2=1.2, n2=40

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Textbook Question

Testing a Difference Other Than Zero Sometimes a researcher is interested in testing a difference in means other than zero. In Exercises 27 and 28, you will test the difference between two means using a null hypothesis of Ho: μ1-μ2=k, Ho: μ1-μ2>=k or Ho: μ1-μ2<=k . The standardized test statistic is still

Software Engineer Salaries Is the difference between the mean annual salaries of entry level software engineers in Santa Clara, California, and Greenwich, Connecticut, more than \$4000? To decide, you select a random sample of entry level software engineers from each city. The results of each survey are shown in the figure at the left. Assume the population standard deviations are σ1=\$14,060 and σ2=\$13,050 . At α=0.05, what should you conclude? (Adapted from Salary.com)

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Textbook Question

Constructing Confidence Intervals for μ1-μ2. You can construct a confidence interval for the difference between two population means μ1-μ2 , as shown below, when both population standard deviations are known, and either both populations are normally distributed or both n1>= 30 and n2>=30 . Also, the samples must be randomly selected and independent.

In Exercises 29 and 30, construct the indicated confidence interval for μ1-μ2 .


Architect Salaries Construct a 99% confidence interval for the difference between the mean annual salaries of entry level architects in Denver, Colorado, and Lincoln, Nebraska, using the data from Exercise 28.

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Textbook Question

Explain how to perform a two-sample t-test for the difference between two population means.

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Textbook Question

[APPLET] Tensile Strength

The tensile strength of a metal is a measure of its ability to resist tearing when it is pulled lengthwise. An experimental method of treatment produced steel bars with the tensile strengths (in newtons per square millimeter) listed below.

Experimental Method:

391 383 333 378 368 401 339 376 366 348

The conventional method produced steel bars with the tensile strengths (in newtons per square millimeter) listed below.

Conventional Method:

362 382 368 398 381 391 400410 396 411 385 385 395 371

At , α=0.01 can you support the claim that the experimental method of treatment makes a difference in the tensile strength of steel bars? Assume the population variances are equal.

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