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Ch. 9 - Correlation and Regression
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 9, Problem 9.3.25

"Constructing and Interpreting a Prediction Interval In Exercises 21-30, construct the indicated prediction interval and interpret the results.
25. Mean Wage Construct a 99% prediction interval for the mean annual wage in Exercise 15 when the percentage of employment in STEM occupations is 13% in the industry."

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Identify the regression equation from Exercise 15, which relates the mean annual wage (dependent variable) to the percentage of employment in STEM occupations (independent variable). This equation typically has the form: \(\hat{y}\) = b_0 + b_1 x, where \(\hat{y}\) is the predicted mean wage, b_0 is the intercept, b_1 is the slope, and x is the percentage of employment in STEM occupations.
Calculate the predicted mean wage \(\hat{y}\) for x = 13% by substituting 13 into the regression equation.
Determine the standard error of the prediction, which accounts for both the variability of the estimate of the mean response and the variability of individual observations. The formula for the standard error of prediction at x = x_0 is: SE_{pred} = s \(\sqrt{1 + \frac{1}{n}\) + \(\frac{(x_0 - \bar{x}\))^2}{\(\sum\) (x_i - \(\bar{x}\))^2}}, where s is the standard error of the estimate, n is the sample size, \(\bar{x}\) is the mean of the x values, and x_0 = 13.
Find the critical t-value for a 99% prediction interval with n - 2 degrees of freedom from the t-distribution table. This value corresponds to the desired confidence level and sample size.
Construct the 99% prediction interval using the formula: \(\hat{y}\) \(\pm\) t_{\(\alpha\)/2, n-2} \(\times\) SE_{pred}. Interpret this interval as the range in which we expect the annual wage for an individual industry with 13% employment in STEM occupations to fall with 99% confidence.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Prediction Interval

A prediction interval estimates the range within which a single new observation is expected to fall, with a specified level of confidence. Unlike confidence intervals for the mean, prediction intervals account for both the uncertainty in estimating the mean and the variability of individual data points.
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Regression and Predictor Variables

Regression analysis models the relationship between a dependent variable and one or more independent variables. Here, the percentage of employment in STEM occupations is the predictor used to estimate the mean annual wage, allowing us to predict wages based on STEM employment levels.
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Confidence Level and Interpretation

The confidence level (e.g., 99%) indicates the probability that the constructed interval contains the true value. Interpreting a 99% prediction interval means we are 99% confident that the wage for a new observation with 13% STEM employment falls within the calculated range.
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Related Practice
Textbook Question

"In Exercises 19-22, two variables are given that have been shown to have correlation but no cause-and-effect relationship. Describe at least one possible reason for the correlation.

20. Alcohol use and tobacco use"

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Textbook Question

"Confidence Intervals for y-Intercept and Slope

You can construct confidence intervals for the y-intercept B and slope M of the regression line y = Mx + B for the population by using the inequalities below.

y-intercept B :

b - E < B < b + E

where

E = t_c s_e \(\sqrt{\frac{1}{n}\) + \(\frac{\overline{x}\)^2}{\(\sum\) x^2 - \(\frac{(\Sigma x)^2}{n}\)}}

slope M :

m - E < M < m + E

where

E = \(\frac{t_c s_e}{\sqrt{\sum x^2 - \frac{(\Sigma x)^2}{n}\)}}

The values of m and b are obtained from the sample data, and the critical value t_c is found using Table 5 in Appendix B with n - 2 degrees of freedom.

In Exercises 37 and 38, construct the indicated confidence intervals for B and M using the gross domestic products and carbon dioxide emissions data found in Example 2.

38. 99% confidence interval"

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Textbook Question

"Predicting y-Values In Exercises 3-6, use the multiple regression equation to predict the y-values for the values of the independent variables.

5. Black Cherry Tree Volume The volume (in cubic feet) of a black cherry tree can be modeled by the equation

y =- 52.2+0.3x_1 +4.5x_2

where x_1 is the tree's height (in feet) and x_2 is the tree's diameter (in inches). (Source: Journal of the Royal Statistical Society)

a. x_1 = 70, x_2 = 8.6

b. x_1 = 65, x_2 = 11.0

c. x_1 = 83, x_2 = 17.6

d. x_1 = 87, x_2 = 19.6"

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Textbook Question

1. Two variables have a positive linear correlation. Does the dependent variable increase or decrease as the independent variable increases? What if the variables have a negative linear correlation?

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Textbook Question

"Constructing and Interpreting a Prediction Interval In Exercises 21-30, construct the indicated prediction interval and interpret the results.

23. Points Earned Construct a 90% prediction interval for total points earned in Exercise 13 when the number of goals allowed by the team is 140."

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Textbook Question

1. Interpret the meaning of the coefficient -8.2 in the multiple regression equation y=112.1+0.43x_1-8.2x_2+29.5x_3.

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