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Ch. 9 - Differential Equations
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 9, Problem 9.5.36d

A physiological model A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like a stirred tank. Suppose the blood volume is a four-liter tank that initially has a zero concentration of a particular drug. At time t = 0, an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500 mg/L. The inflow rate is 0.06 L/min. Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.
d. After how many minutes does the drug mass reach 90% of its steady-state level? 

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Identify the variables and parameters: let \(Q(t)\) be the mass of the drug in the blood at time \(t\) (in minutes). The volume \(V\) of the blood compartment is 4 liters, the inflow concentration \(C_{in}\) is 500 mg/L, and the inflow rate \(r\) is 0.06 L/min. The initial mass is \(Q(0) = 0\) mg.
Write the differential equation for the mass of the drug in the blood. Since the blood is well-mixed and volume is constant, the rate of change of drug mass is inflow minus outflow: \[\frac{dQ}{dt} = r \times C_{in} - r \times \frac{Q(t)}{V}\] Here, \(\frac{Q(t)}{V}\) is the concentration in the blood at time \(t\).
Find the steady-state mass \(Q_{ss}\) by setting \(\frac{dQ}{dt} = 0\): \[0 = r \times C_{in} - r \times \frac{Q_{ss}}{V} \implies Q_{ss} = V \times C_{in}\] This represents the mass when the system reaches equilibrium.
Solve the differential equation for \(Q(t)\) with initial condition \(Q(0) = 0\). This is a first-order linear ODE with solution: \[Q(t) = Q_{ss} \left(1 - e^{-\frac{r}{V} t}\right)\] This shows how the drug mass approaches the steady-state over time.
To find the time \(t\) when \(Q(t)\) reaches 90% of \(Q_{ss}\), set \[Q(t) = 0.9 \times Q_{ss}\] Substitute the solution and solve for \(t\): \[0.9 = 1 - e^{-\frac{r}{V} t} \implies e^{-\frac{r}{V} t} = 0.1 \implies t = -\frac{V}{r} \ln(0.1)\] This expression gives the time to reach 90% of the steady-state drug mass.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

First-Order Linear Differential Equations

This problem involves modeling the change in drug concentration over time using a first-order linear differential equation. The rate of change depends on the inflow and outflow rates and the concentration difference, allowing us to describe how the drug mass evolves until it reaches steady state.
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Steady-State Concentration

Steady state occurs when the drug mass in the blood no longer changes with time, meaning the inflow and outflow rates balance. Calculating the steady-state concentration helps determine the maximum drug mass achievable under constant infusion conditions.
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Exponential Approach to Steady State and Time Constants

The drug mass approaches steady state exponentially, characterized by a time constant related to the volume and flow rate. Understanding this exponential behavior allows us to calculate the time required to reach a certain percentage (e.g., 90%) of the steady-state drug mass.
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Related Practice
Textbook Question

52-56. In this section, several models are presented and the solution of the associated differential equation is given. Later in the chapter, we present methods for solving these differential equations.


where P(t) is the population, for t ≥ 0, and r > 0 and K > 0 are given constants.


d. Find lim(t→∞) P(t) and check that the result is consistent with the graph in part (c).

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Textbook Question

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample


d. According to Newton’s Law of Cooling, the temperature of a hot object will reach the ambient temperature after a finite amount of time.

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Textbook Question

U.S. population projections According to the U.S. Census Bureau, the nation’s population (to the nearest million) was 296 million in 2005 and 321 million in 2015. The Bureau also projects a 2050 population of 398 million. To construct a logistic model, both the growth rate and the carrying capacity must be estimated. There are several ways to estimate these parameters. Here is one approach:


d. Estimations of this kind must be made and interpreted carefully. Suppose the projected population for 2050 is 410 million rather than 398 million. What is the value of the carrying capacity in this case?

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Textbook Question

27–30. Predator-prey models Consider the following pairs of differential equations that model a predator-prey system with populations x and y. In each case, carry out the following steps.

d. Identify the four regions in the first quadrant of the xy-plane in which x' and y' are positive or negative.


x′(t) = 2x − 4xy, y′(t) = −y + 2xy

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Textbook Question

A second-order equation Consider the differential equation y''(t) - k²y(t) = 0 where k > 0 is a real number.


d. For a positive real number k, verify that the general solution of the equation may also be expressed in the form y(t) = C₁cosh(kt) + C₂sinh(kt), where cosh and sinh are the hyperbolic cosine and hyperbolic sine, respectively (Section 7.3).

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Textbook Question

17–20. Increasing and decreasing solutions Consider the following differential equations. A detailed direction field is not needed.


d. Sketch the direction field and verify that it is consistent with parts (a)–(c).


y'(t) = (y−2)(y+1)

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